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Blababa [14]
3 years ago
14

Resulting from past and current geoscience processes, Earth's mineral, energy, and groundwater resources are unevenly distribute

d. As humans continue to remove these limited and often non-renewable resources, their distributions significantly change. This map shows some of the world's major tectonic plate boundaries. Volcanic and hydrothermal activity occur as a result of the energy released along these boundaries, creating an ideal environment for the concentration of minerals. Which statement provides another rationale for higher mineral concentrations near plate boundaries compared other parts of the world? A) The speed of mineral formation is increased by the high levels of groundwater found at plate boundaries. B) Sediment from erosion usually deposits near plate boundaries, and volcanic activity causes it to form minerals. C) Rocks with high mineral concentrations buried deep in the mantle can be pushed near the surface as plates move. D) The magnetic pull of Earth's mantle is strongest at plate boundaries, pulling minerals in Earth's crust toward them.
Physics
1 answer:
Fudgin [204]3 years ago
8 0

Answer: C) Rocks with high mineral concentrations buried deep in the mantle can be pushed near the surface as plates move.

Explanation:

Usa test prep

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The force needed to move an object 14 meters with 83 joules of work is what?
AleksandrR [38]
W=F*D
83J=F*14
83/14=F
5.92N
8 0
3 years ago
A current of 200 mA through a conductor converts 40 joules of electrical energy into heat in 30 second
Komok [63]

Answer:

V = 6.65 [volt]

Explanation:

First, we must calculate the power by means of the following equation, where the voltage is related to the energy produced or consumed in a given time.

P=E/t\\P = 40/30\\P = 1.33[s]

Using the power we can calculate the voltage, by means of the following equation that relates the voltage to the current.

P=V*I

where:

V = voltage [Volts]

I = current = 200 [mA] = 0.2 [A]

V = 1.33/0.2\\V = 6.65 [volt]

8 0
4 years ago
Can someone please help?? I don’t understand this material!!!
Debora [2.8K]

Answer:

1)

When the person throws the ball away, the person rolls backward. This is due to the law of conservation of momentum: in fact, the total momentum of the person+ball system must be conserved.

At the beginning,

p_i=0

after throwing the ball, the total momentum is the sum of the momentum of the person and of the ball:

p_f=p_p + p_b

Since momentum is conserved,

p_i = p_f\\0=p_p+p_b

So

p_p = -p_b

Therefore, the person has equal momentum (in magnitude) but opposite direction to the ball, so the person rolls backward.

However, if the person hold to the ball, then they will have same momentum (moving in the same direction). In order to conserve the total momentum (which was zero at the beginning), the only possible solution is that

p_p=p_b=0

which means that both the person and the ball will remain at rest. This is because there are no external forces acting on the system, so the system cannot move.

2)

The change in momentum of an object is given by

\Delta p=m(v-u)

where

m is the mass of the object

v is its final velocity

u is the initial velocity

For the clay ball in this problem, we have:

m = 50 g = 0.050 kg

v = 0 m/s (it sticks on the wall)

u = 1 m/s

So its change in momentum is

\Delta p_c=(0.050)(0-1)=-0.050 kg m/s

For the superball, we have:

m = 50 g = 0.050 kg

v = -0.8 m/s (it bounces back)

u = 1 m/s

So its change in momentum is

\Delta p_s = (0.050)(-0.8-1)=-0.09 kg m/s

So, the superball has a greater change in momentum (in magnitude).

3a)

According to Newton's third law of motion:

"When an object A exerts a force (action force) on an object B, then object B exerts an equal and opposite force (reaction force) on object A".

Here, we have a Hummer and a Beetle colliding head-on: we can identify them as object A and object B. Therefore, according to Newton's third law:

- The action force is the force of impact exerted by the Hummer on the Beetle

- The reaction force is the force of impact exerted by the Beetle on the Hummer

And according to the Law, the two forces are equal in magnitude: so, the two vehicles experience the same force of impact.

3b)

The change in momentum of each vehicle during the collision can be written as

\Delta p = F\Delta t (1)

where

\Delta p is the change in momentum

F is the force experienced by the vehicle

\Delta t is the duration of the collision

in part 3a), we said that the two vehicles experience the same force in the collision.

Moreover, the duration of the collision, \Delta t, is the same for the two vehicles.

As a result, according to formula (1), the two vehicles have same change in momentum (however, the directions would be opposite, since they experience force in opposite directions).

3c)

According to Newton's second law of motion, the acceleration of an object is given by:

a=\frac{F}{m}

where

F is the force experienced by the object

m is its mass

a is its acceleration

In part 3a), we stated that the force experienced by the Beetle and the Hummer is the same. However, the mass of the Beetle is smaller than the mass of the Hummer: from the equation we see that the acceleration is inversely proportional to the mass, therefore the Beetle will experience a greater acceleration.

4a)

The force experienced by the dashboard on the car is given by:

F=\frac{\Delta p}{\Delta t}

Where

\Delta p is the change in momentum

\Delta t is the duration of the collision

In a padded dashboard, the duration of the collision \Delta t is larger than the duration of the collision for a hard dashboard. According to the equation above, the force experienced by the dashboard (and so, the car) is inversely proportional to the duration of the collision: therefore, since the padded dashboard has a larger \Delta t, it will experience a smaller force than the hard dashboard.

4b)

The force experienced by the climber if falling is given by

F=\frac{\Delta p}{\Delta t}

Where

F is the force experienced by the climber

\Delta p is his change in momentum

\Delta t is the duration of fall

Nylon is a very elastic material, so it is able to "soften" the fall by stretching a lot. As a result, the nylon increases the value of \Delta t in the formula. Since the force experienced by the climber is inversely proportional to \Delta t, the climber will feel less force thanks to the nylon.

4c)

This technique is used to exploit the "push" given by the second car of the train to the first car when the brakes are applied.

At first, the engine is started, and the first car starts accelerating, pulling the second car (and the following cars). Then, the brakes are applied on the first car: however, the second car keeps moving by inertia, so then it gives a push forward on the first car. Then, this action is repeated several times, so that this push exerted by the second car is exploited several times.

3 0
3 years ago
A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration. At one time it is r
aivan3 [116]

Answer:

Explanation:

Given that,

Initial angular velocity is 0

ωo=0rad/s

It has angular velocity of 11rev/sec

ωi=11rev/sec

1rev=2πrad

Then, wi=11rev/sec ×2πrad

wi=22πrad/sec

And after 30 revolution

θ=30revolution

θ=30×2πrad

θ=60πrad

Final angular velocity is

ωf=18rev/sec

ωf=18×2πrad/sec

ωf=36πrad/sec

a. Angular acceleration(α)

Then, angular acceleration is given as

wf²=wi²+2αθ

(36π)²=(22π)²+2α×60π

(36π)²-(22π)²=120πα

Then, 120πα = 8014.119

α=8014.119/120π

α=21.26 rad/s²

Let. convert to revolution /sec²

α=21.26/2π

α=3.38rev/sec

b. Time Taken to complete 30revolution

θ=60πrad

∆θ= ½(wf+wi)•t

60π=½(36π+22π)t

60π×2=58πt

Then, t=120π/58π

t=2.07seconds

c. Time to reach 11rev/sec

wf=wo+αt

22π=0+21.26t

22π=21.26t

Then, t=22π/21.26

t=3.251seconds

d. Number of revolution to get to 11rev/s

∆θ= ½(wf+wo)•t

∆θ= ½(0+11)•3.251

∆θ= ½(11)•3.251

∆θ= 17.88rev.

5 0
3 years ago
Read 2 more answers
If Mike does 25.5 J of work lifting a book 1.5 m onto a shelf what is the mass of the book in kilograms
Akimi4 [234]
Lifting the book means that the object gains gravitational potential energy. GPE=mass*gravitational field strength*height, ∴m=GPE/gh, m=25.5/10*1.5=1.7 kg
7 0
3 years ago
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