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Blababa [14]
3 years ago
14

Resulting from past and current geoscience processes, Earth's mineral, energy, and groundwater resources are unevenly distribute

d. As humans continue to remove these limited and often non-renewable resources, their distributions significantly change. This map shows some of the world's major tectonic plate boundaries. Volcanic and hydrothermal activity occur as a result of the energy released along these boundaries, creating an ideal environment for the concentration of minerals. Which statement provides another rationale for higher mineral concentrations near plate boundaries compared other parts of the world? A) The speed of mineral formation is increased by the high levels of groundwater found at plate boundaries. B) Sediment from erosion usually deposits near plate boundaries, and volcanic activity causes it to form minerals. C) Rocks with high mineral concentrations buried deep in the mantle can be pushed near the surface as plates move. D) The magnetic pull of Earth's mantle is strongest at plate boundaries, pulling minerals in Earth's crust toward them.
Physics
1 answer:
Fudgin [204]3 years ago
8 0

Answer: C) Rocks with high mineral concentrations buried deep in the mantle can be pushed near the surface as plates move.

Explanation:

Usa test prep

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A 2.0 kg particle moves in a circle of radius 3.1 m. As you look down on the plane of its orbit, the particle is initially movin
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given,

L(t) = 10 - 3.5 t

mass of particle = 2 Kg

radius of the circle = 3.1 m

a) torque

    τ = \dfrac{dL}{dt}

    τ = \dfrac{d}{dt}(10 - 3.5 t)

    τ = -3.5 N.m

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L decreases the angular acceleration upward. so, net torque is upward.

b) Moment of inertia of the particle

    I = m R^2

    I = 2 x 3.1²

    I = 19.22 kg.m²

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    ω = \dfrac{L}{I}

    ω = \dfrac{10 - 3.5 t}{19.22}

    ω = 0.520 - 0.182 t

  A = 0.52 rad/s             B = -0.182 rad/s²

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what will be the focal lenght of a combined lens made by contact of two lenses of power +3D and -2D.​
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\\ \bull\tt\dashrightarrow P=P_1+P_2

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Now

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\\ \bull\tt\dashrightarrow f=\dfrac{1}{1}

\\ \bull\tt\dashrightarrow f=1m

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