A dissipative process is a process in which force is transformed from some initial form to some final form; REMEMBER, the capacity of the final form to do mechanical work is less than that of the initial form...
Task #1: Poison ivy is a weed that grows in New York State. It’s synthesizes an oil, urushiol, that causes skin rashes. Researchers have found that if poison ivy grows in an environment that contains an increased concentration of carbon dioxide, the plants grow larger, faster, and produce more urushiol. Because carbon dioxide levels in the atmosphere are rising, poison ivy might become a hazard to people who work or vacation outdoors. In order to verify this research, experiments must be carried out. Design an experiment to test whether poison ivy is affected by air containing higher than normal concentrations of carbon dioxide.
State one way the control group should be treated differently from the experimental group.
Answer: 53 dal
Explanation: 5.3x10=53, to get dal you have to multiply by 10 to get 5.3x10=53.
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Answer:
ΔF = 0.21 N
Explanation:
For this exercise that does not ask for the change in weight we must use the law of universal gravitation
F = G M m / r²
where r is the distance from the center of the Earth, in the lower part of the building is
r =
for the upper part of the building h = 1 mile = 1609.34 m
r =R_{e} + h
the weight or the force of attraction of gravity on the floor is F = 817 N, therefore the equation remains
817 = (G M m / R_{e}²)
let's find this force for the top of the building
F` = G M m / (R_{e} + h)²
let's take out R_{e} common factor
F ’= (G M m / R_{e}²) 1 / (1 + h / R_{e})²2
F ’= (G M m R_{e}²) (1 + h / R_{e})⁻²
as the quantity h /R_{e} = 1609 / 6.37 10⁶ << 1 we can make a series space
(1 + x)⁻² = 1 -2 x + ...
we substitute
F ’= (GMm /R_{e}²) (1 - 2 1609 / 6.37 10⁶)
F ’= (GMm /R_{e}²) (1 - 2.53 10⁻⁴) = (GMm / R_{e}²) 0.99974
F ’= 817 0.99974
F ’= 816.79 N
weight Change
ΔF = ΔW = 817 - 816.79
ΔF = 0.21 N
as we see this is a very small amount
Answer:
magnitude is 2.52 m with 66.15° north east
Explanation:
given data
displace 1 = 3.45 m north = 3.45 j
displace 2 = 1.53 m southeast = 1.53 cos(315) i + sin(315) j
displace 3 = 0.877 m southwest = 0.877 cos(225) i- sin(225) j
to find out
displacement and direction
solution
we consider here direction i as east and direction j as north
so here
displacement = displace 1 + displace 2 + displace 3
displacement = 3.45 j + 1.53 cos(315) i + sin(315) j + 0.877 cos(225) i- sin(225) j
displacement = 3.45 j + 1.081 i -1.0818 j - 0.062 i -0.062 j
displacement = 1.019 i + 2.306 j
so magnitude
magnitude =
magnitude = 2.52
and
angle will be = arctan(2.306/1.019)
angle = 1.15470651 rad
angle is 66.15 degree
so magnitude is 2.52 m with 66.15° north east