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valina [46]
3 years ago
7

A 0.18-kg turntable of radius 0.32 m spins about a vertical axis through its center. A constant rotational acceleration causes t

he turntable to accelerate from 0 to 24 revolutions per second in 8.0 s.Calculate the rotational acceleration.
Physics
1 answer:
borishaifa [10]3 years ago
4 0

Answer:

Angular acceleration will be 18.84rad/sec^2

Explanation:

We have given that mass m = 0.18 kg

Radius r = 0.32 m

Initial angular velocity \omega _i=0rev/sec

And final angular velocity \omega _f=24rev/sec

Time is given as t = 8 sec

From equation of motion

We know that \omega _f=\omega _i+\alpha t

24=0+\alpha \times 8

\alpha =3rev/sec^2=3\times 2\times \pi rad/sec^2=18.84rad/sec^2

So angular acceleration will be 18.84rad/sec^2

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                    d = \frac{w}{F}

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(ii)  For w = 36 J, and F = 12 N then value of d will be as follows.

                    d = \frac{w}{F}

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                    d = \frac{w}{F}

                       = \frac{36 J}{6 N}

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                    d = \frac{w}{F}

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