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Artemon [7]
3 years ago
7

Which substances will make a salt when combined? Vinegar and antacids Soda and wine Soap and ammonia Fertilizer and detergent

Chemistry
2 answers:
Mariulka [41]3 years ago
8 0

Salt is usually formed during neutralization reactions, that is the reaction of an acid and a base. This is illustrated as follows:

<span>HX + YOH -->  XY + H2O</span>

where XY is the salt

 

From the given choices, the only pair of acid and base is:

<span>Vinegar and antacids</span>

alukav5142 [94]3 years ago
4 0

Answer is: vinegar and antacids.

Neutralizationis is reaction in which an acid (in this example vinegar or acetic acid CH₃COOH)  and a base (in this example antacid, aluminium hydroxide, magnesium hydroxide or some other base) react quantitatively with each other.

Balanced chemical reaction of vinegar and antacid:

2CH₃COOH(aq) + Mg(OH)₂(aq) → (CH₃COO)₂Mg(s) + 2H₂O(l).

Magnesium acetate ((CH₃COO)₂Mg) is a salt.

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maxonik [38]

Answer:

10 g/ml

Explanation:

divide mass by volume means divide 1000 by 100 and your answer will be 10

4 0
3 years ago
2) Which liberates the most energy?
evablogger [386]

Answer: F(g)+e^-\rightarrow F^-(g)

Explanation:

Electron gain enthalpy is defined as energy released on addition of electron to an isolated gaseous atom.  

The amount of energy released will be maximum when the tendency to attract electrons is maximum. As flourine has atomic number of 9 and has electronic configuration of 2,7. It can readily gain 1 electron to attain stable noble gas configuration and hence liberates maximum energy.

F(g)+e^-\rightarrow F^-(g)

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3 years ago
Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.
Vsevolod [243]

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

<h3>Balanced equation </h3>

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₃PO₄ (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 3

<h3>How to determine the volume of Ca(OH)₂ </h3>
  • Molarity of acid, H₃PO₄ (Ma) = 0.390 M
  • Volume of acid, H₃PO₄ (Va) = 24.5 mL
  • Molarity of base, Ca(OH)₂ (Mb) = 0.279 M
  • Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

Learn more about titration:

brainly.com/question/14356286

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What is the percent of composition by mass of hydrogen in NH4HCO3 (gram-formualmass=79 grams/mole)?
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5/79=0.063
0.063 x 100 = 6.3%
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