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2 years ago

Which substances will make a salt when combined? Vinegar and antacids Soda and wine Soap and ammonia Fertilizer and detergent

2 answers:

8 0

Salt is usually formed during neutralization reactions, that is the reaction of an acid and a base. This is illustrated as follows:

HX + YOH --> XY + H2O

where XY is the salt

From the given choices, the only pair of acid and base is:

Vinegar and antacids

alukav5142 [94]2 years ago

4 0

Answer is: vinegar and antacids.

Neutralizationis is reaction in which an acid (in this example vinegar or acetic acid CH₃COOH) and a base (in this example antacid, aluminium hydroxide, magnesium hydroxide or some other base) react quantitatively with each other.

Balanced chemical reaction of vinegar and antacid:

2CH₃COOH(aq) + Mg(OH)₂(aq) → (CH₃COO)₂Mg(s) + 2H₂O(l).

Magnesium acetate ((CH₃COO)₂Mg) is a salt.

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Question 2: Which of the following is NOT true about streams?

mafiozo [28]

Answer:

q 3 c q 2 d

Explanation:

8 0

3 years ago

How would you separate a mixture of water, sand, salt and iron filings into its four component parts

kipiarov [429]

Magnet to remove the iron, filter paper (or some filter that could trap sand) to remove the sand, and heat up the salt and water, causing the water to evaporate to separate them.

3 0

3 years ago

Predict the sign of the entropy change, ΔS∘, for each of the reaction displayed.Drag the appropriate items to their respective b

Sonja [21]

Answer:

Ag+(aq)+Br−(aq)→AgBr(s) NEGATIVE

CaCO3(s)→CaO(s)+CO2(g)2 POSITIVE

NH3(g)→N2(g)+3H2(g) POSITIVE

2Na(s)+Cl2(g)→2NaCl(s) NEGATIVE

C3H8(g)+5O2(g)→3CO2(g) +4H2O(g) POSITIVE

I2(s)→I2(g) POSITIVE

Explanation:

We have to remember, to solve this problem, that the entropy of a gas is higher than that of a liquid which in turn is higher than the solid. Therefore, comparing the reactants and products look for changes in the state of reactants and products. We also have to look for the increase or decrease of moles of each state based on the balanced chemical reaction.

Ag+(aq)+Br−(aq)→AgBr(s)

The reaction product is a single solid and the the reactants were 2 species in solution. The change in entropy is negative.

CaCO3(s)→CaO(s)+CO2(g)2

Here we have a solid reactant and we have a solid product plus a gas product. The change in entropy is positive.

NH3(g)→N2(g)+3H2(g)

We have 4 mole gases as products starting from 1 mol reactant gas, the entropy has increased.

2Na(s)+Cl2(g)→2NaCl(s)

In this reaction 2 mol solid Na and 1 mol Cl₂ gas are converted into 2 mol solid NaCl, the entropy has decreased.

C3H8(g)+5O2(g)→3CO2(g) +4H2O(g)

The products are 7 mol of gas versus 6 mol of gas reactants and therefore entropy has increased.

I2(s)→I2(g)

1 mol solid I₂ goes into 1 mol gas making the change in the entropy higher.

4 0

3 years ago

What is the mass of 4.57 x 1021 molecules of ammonia (NH3)?

Alex17521 [72]

Answer:

4665.97

Explanation:

5 0

2 years ago

If the enantiomeric excess of a mixture is 75%, what are the % compositions of the major and minor enantiomer?

Maru [420]

Let us say that R is the major enantiomer, while S is the minor enantiomer, therefore the formula for enantiomeric excess (ee) is:

ee = (R – S) * 100%

Let us further say that the fraction of R is x (R = x), and therefore fraction of S is 1 – x (S = 1 – x), therefore:

75 = (x – (1 – x)) * 100

75 = 100 x – 100 + 100 x

200 x = 175

x = 0.875

Summary of answers:

R = major enantiomer = 0.875 or 87.5%

S = minor enantiomer = (1 – 0.875) = 0.125 or 12.5%

7 0

3 years ago