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HACTEHA [7]
2 years ago
6

You push your friend up the street with a force of 200N. How much work did you do if you traveled 15m?

Chemistry
1 answer:
VARVARA [1.3K]2 years ago
4 0

Answer:

3000J

Explanation:

Formula: Work = Force × Distance

Solution: Work = 200N × 15m

Answer = 3000N/m or 3000J

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Is it true that an atom has 3 subatomic particles with a negative nucleus and the neutrons outside the the nucleus
Nostrana [21]

Answer: atoms do have 3 subatomic particles but the nucleus is positive and the nucleus consists of protons and neutrons. Its positive because neutrons have no charge and protons have a positive charge. There are only electrons on the shells so no neutrons or protons on the shells

Explanation:

5 0
2 years ago
What is the mole fraction of O2O2 in a mixture of 15.1 gg of O2O2, 8.19 gg of N2N2, and 2.46 gg of H2H2
SVETLANKA909090 [29]

Answer:

Mole fraction O₂=  0.43

Explanation:

Mole fraction is the moles of gas/ total moles.

Let's determine the moles of each:

Moles O₂ → 15.1 g / 16 g/mol = 0.94

Moles N₂  →  8.19 g / 14 g/mol = 0.013

Moles H₂  → 2.46 / 2 g/mol = 1.23

Total moles = 2.183

Mole fraction O₂= 0.94 / 2.183 → 0.43

3 0
3 years ago
A container is filled with helium gas. It has a volume of 2.25 liters and contains 9.00 moles of helium. How many moles of heliu
Darina [25.2K]

Answer: There are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

Explanation:

Given: V_{1} = 2.25 L,     n_{1} = 9.0 mol

V_{2} = 1.85 L,            n_{2} = ?

Formula used to calculate the moles of helium are as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\

Substitute the values into above formula as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{2.25 L}{9.0 mol} = \frac{1.85 L}{n_{2}}\\n_{2} = \frac{1.85 L \times 9.0 mol}{2.25 L}\\= 7.4 mol

Thus, we can conclude that there are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.

7 0
2 years ago
What is the volume when the density is 7.83g/ml and 19.6 grams?
insens350 [35]
To fine volume, you have to divide the mass by the density of the substance. in this, you’ll do 19.6/7.83=2.50
4 0
3 years ago
Naphthalene combustion may be used to calibrate the heat capacity of a bomb calorimeter. The heat of combustion of naphthalene i
tino4ka555 [31]

Answer:

.

Explanation:

5 0
3 years ago
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