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lapo4ka [179]
3 years ago
10

Read the given equation. 2Na + 2H2O → 2NaOH + H2

Chemistry
2 answers:
PolarNik [594]3 years ago
8 0
<h3>Answer:</h3>

                17.25 g of Na

<h3>Explanation:</h3>

                        The balance chemical equation is as follow,

                              2 Na + 2 H₂O    →    2 NaOH + H₂

As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ (1 L) volume.

Then, according to equation,

            22.4 L (1 mol) H₂ was produced by  =  46 g (2 mol) of Na

Then,

                     8.40 L H₂ gas will be produced by  =  X g of Na

Solving for X,

                      X =  (8.40 L × 46 g) ÷ 22.4 L

                      X =  17.25 g of Na

Allisa [31]3 years ago
3 0

Answer:

A) 17.2 grams

Explanation:

I took the quiz and A was correct!

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<span>If 23% is saturated, so the number of binding sites occupied is 0.92 x 10^6 binding sites or 9.2 x 10^5 binding sites.</span>

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A sample of gas contains 0.1900 mol of CO(g) and 0.1900 mol of NO(g) and occupies a volume of 22.0 L. The following reaction tak
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Answer:

V₂ = 16.5 L

Explanation:

To solve this problem we use <em>Avogadro's law, </em>which applies when temperature and pressure remain constant:

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In this case, V₁ is 22.0 L, n₁ is [mol CO + mol NO], V₂ is our unknown, and n₂ is [mol CO₂ + mol N₂].

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<em>We use the reaction to calculate n₂</em>:

2CO(g) + 2NO(g) → 2CO₂(g) + N₂(g)

  • mol CO₂:

0.1900 mol CO * \frac{2molCO_{2}}{2molCO} = 0.1900 mol CO₂

  • mol N₂:

0.1900 mol NO * \frac{1molN_{2}}{2molNO} = 0.095 mol N₂

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Molar Mass of Calcium carbonate:-

\\ \sf\longmapsto CaCO_3

\\ \sf\longmapsto 40u+12u+3(16u)

\\ \sf\longmapsto 52u+48u

\\ \sf\longmapsto 100u

\\ \sf\longmapsto 100g/mol

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\boxed{\sf No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}}

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Now

\boxed{\sf No\:of\:molecules=No\;of\:moles\times Avagadro\: No}

\\ \sf\longmapsto 0.1\times 6.023\times 10^{23}

\\ \sf\longmapsto 6.023\times 10^{22}molecules

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