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lapo4ka [179]
3 years ago
10

Read the given equation. 2Na + 2H2O → 2NaOH + H2

Chemistry
2 answers:
PolarNik [594]3 years ago
8 0
<h3>Answer:</h3>

                17.25 g of Na

<h3>Explanation:</h3>

                        The balance chemical equation is as follow,

                              2 Na + 2 H₂O    →    2 NaOH + H₂

As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ (1 L) volume.

Then, according to equation,

            22.4 L (1 mol) H₂ was produced by  =  46 g (2 mol) of Na

Then,

                     8.40 L H₂ gas will be produced by  =  X g of Na

Solving for X,

                      X =  (8.40 L × 46 g) ÷ 22.4 L

                      X =  17.25 g of Na

Allisa [31]3 years ago
3 0

Answer:

A) 17.2 grams

Explanation:

I took the quiz and A was correct!

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Na2CO3 reacts with dil.HCl to produce NaCl, H2O and CO2. If 21.2 g of pure Na2CO3 are added in a solution containing 21.9g HCl ,
puteri [66]

Answer:

See explanation

Explanation:

Equation of the reaction;

Na2CO3(aq) + 2HCl(aq) -------> 2NaCl(aq) + H2O(l) + CO2(g)

Number of moles of Na2CO3 = 21.2g/106g/mol = 0.2 moles Na2CO3

Number of moles of HCl = 21.9g/36.5g/mol = 0.6 moles of HCl

1 mole of Na2CO3 reacts with 2 moles of HCl

0.2 moles of Na2CO3 reacts with 0.2 × 2/1 = 0.4 moles of HCl

Hence Na2CO3 is the limiting reactant

Since there is 0.6 moles of HCl present, the number of moles of excess reagent=

0.6 moles - 0.4 moles = 0.2 moles of HCl

1 mole of Na2CO3 forms 1 mole of water

0.2 moles of Na2CO3 forms 0.2 moles of water

Number of molecules of water formed = 0.2 moles × 6.02 × 10^23 = 1.2 × 10^23 molecules of water

1 mole of Na2CO3 yields 1 mole of CO2

0.2 moles of Na2CO3 yields 0.2 moles of CO2

1 mole of CO2 occupies 22.4 L

0.2 moles of CO2 occupies 0.2 × 22.4 = 4.48 L at STP

Hence;

V1=4.48 L

T1 = 273 K

P1= 760 mmHg

T2 = 27°C + 273 = 300 K

P2 = 760 mmHg

V2 =

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 760 × 4.48 × 300/760 × 273

V2= 4.9 L

The limiting reactant is the reactant that determines the amount of product formed in a reaction. When the limiting reactant is exhausted, the reaction stops.

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andreyandreev [35.5K]

Answer:

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Explanation:

CH18

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Answer:

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