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2 years ago

Read the given equation. 2Na + 2H2O → 2NaOH + H2

Chemistry

2 answers:

PolarNik [594]2 years ago

8 0

<h3>Answer:</h3>

17.25 g of Na

<h3>Explanation:</h3>

The balance chemical equation is as follow,

2 Na + 2 H₂O → 2 NaOH + H₂

As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ (1 L) volume.

Then, according to equation,

22.4 L (1 mol) H₂ was produced by = 46 g (2 mol) of Na

Then,

8.40 L H₂ gas will be produced by = X g of Na

Solving for X,

X = (8.40 L × 46 g) ÷ 22.4 L

X = 17.25 g of Na

Allisa [31]2 years ago

3 0

Answer:

A) 17.2 grams

Explanation:

I took the quiz and A was correct!

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Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

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$\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%$

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$\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%$

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

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