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Afina-wow [57]
3 years ago
15

Two linear equations are shown in the graph.

Mathematics
2 answers:
Fed [463]3 years ago
7 0

count the lines horizontally and vertically to see where the lines connect

 x = left to right

y = up and down.

 the black lines are the origins ( 0,0)

 so 3 to the right of a black line and 3 up from the black line equals (3,3)

 Answer is B

Mnenie [13.5K]3 years ago
6 0
So its rise over run.
So you would go over 3, and up 3. So now you have your plots.
The correct answer would be (3,3)
I hope this helps.
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Triangle ABC has angle measures as shown below. Using the information in the diagram, and the value of x that you calculated in
Minchanka [31]

Answer:

x=29

Step-by-step explanation:

180-87=93

93=3x+6

-6        -6

--------------

93=3x

/3    /3

-------------

29=x

x=29

*all angles in a triangle add up to 180. So, 35+52=93. 180-93=87.

C=87

5 0
3 years ago
Hi can anyone solve and give a explaination plz? its for a friend
lbvjy [14]

6.75

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4.50

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2.25

-2.25

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5 0
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4 years ago
Factorise each of the following algebraic expressions completely,
LekaFEV [45]

Answer:

see explanation

Step-by-step explanation:

(a)

Given

2k - 6k² + 4k³ ← factor out 2k from each term

= 2k(1 - 3k + 2k²)

To factor the quadratic

Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)

The factors are - 1 and - 2

Use these factors to split the k- term

1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )

1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term

= (1 - k)(1 - 2k)

1 - 3k + 2k² = (1 - k)(1 - 2k) and

2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)

(b)

Given

2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )

= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term

= (x - 2y)(2a + 3b)

8 0
3 years ago
What is the solution of the system? Use either the substitution method or the elimination method. 4x + 2y = 104x + 2y = 10 x − y
bixtya [17]
4x+2y=10 Equation 1
x-y=13 Equation 2
Solving by substitution method.
Isolate x from equation 2.
x=y+13
Substitute value of x in equation 1
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6y=-42
y=-7
Now substitute value of y in x=y+13
x=-7+13
x=6

Answer: (6,-7)
8 0
4 years ago
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