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Harlamova29_29 [7]
3 years ago
13

Of the dogs at the dog show,

Mathematics
2 answers:
pochemuha3 years ago
7 0
(1/12)* (3/10)= 1/40

Final answer: 1/40 of the dogs at the show were English Foxhounds.

Hope this would help~
Olin [163]3 years ago
5 0
So, let's say that all the dogs had a number of x.

then 1/12 x were the Hound Group dogs.

then, out of the Hound Group,, that is 1/12 x, 3/10 were English Foxhounds.

For this, we need to multiply the fractions:

\frac{1}{12}x* \frac{3}{10} = \frac{3}{120}x =\frac{1}{40}x

so of all the dogs at the show, the English Foxhunds were a 1/40 fraction,  
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\triangle LMN \cong \triangle OPQ

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3 years ago
Prove the divisibility:<br><br>45^45·15^15 by 75^30
garri49 [273]

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3^{75}.

Step-by-step explanation:

We have been an division problem: \frac{45^{45}*15^{15}}{75^{30}}.

We will simplify our division problem using rules of exponents.

Using product rule of exponents (a*b)^n=a^n*b^n we can write:

45^{45}=(9*5)^{45}=9^{45}*5^{45}

15^{15}=(3*5)^{15}=3^{15}*5^{15}

75^{30}=(15*5)^{30}=15^{30}*5^{30}

Substituting these values in our division problem we will get,

\frac{9^{45}*5^{45}*3^{15}*5^{15}}{15^{30}*5^{30}}

Using power rule of exponents a^n*a^m=a^{n+m} we will get,

\frac{9^{45}*5^{(45+15)}*3^{15}}{15^{30}*5^{30}}

\frac{9^{45}*5^{60}*3^{15}}{15^{30}*5^{30}}

Using product rule of exponents (a*b)^n=a^n*b^n we will get,

\frac{(3*3)^{45}*5^{60}*3^{15}}{(3*5)^{30}*5^{30}}

\frac{3^{45}*3^{45}*5^{60}*3^{15}}{3^{30}*5^{30}*5^{30}}

Using power rule of exponents a^n*a^m=a^{n+m} we will get,

\frac{3^{(45+45+15)}*5^{60}}{3^{30}*5^{(30+30)}}

\frac{3^{105}*5^{60}}{3^{30}*5^{60}}

\frac{3^{105}}{3^{30}}

Using quotient rule of exponent \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{3^{105}}{3^{30}}=3^{105-30}

3^{105-30}=3^{75}

Therefore, our resulting quotient will be 3^{75}.

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