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2 answers:
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Answer:
The original length was 41 inches and the original width was 16 inches
Step-by-step explanation:
Let
x ----> the original length of the piece of metal
y ----> the original width of the piece of metal
we know that
When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box
The dimensions of the box are
The volume of the box is equal to
so
simplify
-----> equation A
Remember that
The piece of metal is 25 in longer than it is wide
so
----> equation B
substitute equation B in equation A
solve for y
Solve the quadratic equation by graphing
using a graphing tool
The solution is y=16
see the attached figure
Find the value of x
therefore
The original length was 41 inches and the original width was 16 inches
9514 1404 393
Answer:
x = 8/7
Step-by-step explanation:
.2(.7x-5)+0.2=1.4(x-1.6) . . . . given
Eliminating parentheses, we have ...
0.14x -1 +0.2 = 1.4x -2.24
1.44 = 1.26x . . . . . . . add 2.24-0.14x to both sides
x = 1.44/1.26 . . . . . . divide by the coefficient of x
x = 8/7 . . . . . . . . . . .simplify the fraction
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As a repeating decimal, the value of x is ...
However, the notation 1.(142857) is usually reserved for the case where the contents of parentheses are being multiplied by the factor in front. You would need to consult your instructions to see how the decimal version of the answer should be entered. (Quite often, rounding is suggested.)
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<em>Additional comment</em>
The equation in the text of your question is different from the one in the picture. We have answered for the one in the picture. The text asks for the solution of a quadratic. Those two solutions are approximately 1.085 and 16.057.