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ruslelena [56]
3 years ago
10

If there are 8 minutes in commercials and each one was 25 seconds long how many commercials would ther be

Mathematics
1 answer:
kondaur [170]3 years ago
8 0
8 minutes is 480 seconds.
So if you divide 480 by 25 you get 19 with a remainder of 5/25. You can only play 19 complete commercials in 8 minutes if they are 25 seconds long.
You might be interested in
X divided by 2 - x divided by 3 = 4
Tpy6a [65]
X would be 24 
24 divided by 2 - 24 divided by 3 = 4 
7 0
3 years ago
How did u get 4/3. Because I’m confused
Svet_ta [14]
What’s the original question and I can help!
5 0
3 years ago
Describe lengths of three segments that could not be used to form a triangle. Segments with lengths of 5 in., 5 in., and ______
Vesna [10]

Answer:

c = 11

Step-by-step explanation:

Given

Let the three sides be a, b and c

Such that:

a = b= 5

Required

Find c such that a, b and c do not form a triangle

To do this, we make use of the following triangle inequality theorem

a + b > c

a + c > b

b + c > a

To get a valid triangle, the above inequalities must be true.

To get an invalid triangle, at least one must not be true.

Substitute: a = b= 5

5 + 5 > c ===> 10 > c

5 + c > 5  ===> c > 5 - 5 ===> c > 0

5 + c > 5  ===> c > 5 - 5 ===> c > 0

The results of the inequality is: 10 > c and c > 0

Rewrite as: c > 0 and c < 10

0 < c < 10

This means that, the values of c that make a valid triangle are 1 to 9 (inclusive)

Any value outside this range, cannot form a triangle

So, we can say:

c = 11, since no options are given

8 0
2 years ago
Please help solve the inequality.
gulaghasi [49]

Answer:

Are there two you're asking for?

#2: x ≥ 9

#3: x > -2

Step-by-step explanation:

#2 Work:

x - 13 ≥ -4

Step 1: Add 13 to both sides

x - 13 + 13 ≥ -4 + 13

Add -4 and 13 to get 9.

x ≥ 9

#3 Work:

x/2 > -1

Multiply both sides by 2. Since 2 is positive, the inequality direction remains the same

x/2 * 2 > -1 * 2

x > -2

5 0
2 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

6 0
3 years ago
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