vertex = (3,- 5 )
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
the x-coordinate of the vertex is
= -
y = x² - 6x + 4 is in standard form
with a = 1, b = - 6 and c = 4, hence
= -
= 3
substitute this value into the equation for y- coordinate
y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5
vertex = (3, - 5 ) → second table
Answer:
Bottom left graph
Step-by-step explanation:
We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:
−2x + y ≤ 4 >> Original Standard Equation
+ 2x + 2x
_________
y ≤ 2x + 4 >> Slope-Intercept Equation
−2[0] + 0 ≤ 4
0 ≤ 4 ☑ [We shade the part of the graph that CONTAINS THE ORIGIN, which is the right side.]
[We shade the part of the graph that does not contain the origin, which is the left side.]
So, now that we got that all cleared up, we can tell that the graphs share a region in between each other and that they both have POSITIVE <em>RATE OF CHANGES</em> [<em>SLOPES</em>], therefore the bottom left graph matches what we want.
** By the way, you meant because this inequality in each graph is a <em>dashed</em><em> </em><em>line</em>. It is ALWAYS significant that you be very cautious about which inequalities to choose when graphing. Inequalities can really trip some people up, so once again, please be very careful.
I am joyous to assist you anytime.
Answer:
w = 242
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
Step 2: Subtract 253 from both sides.
Step 3: Divide both sides by -1.
Step 4: Check if solution is correct.
Therefore, w = 242.
Have a lovely rest of your day/night.