To start with solving this
problem, let us assume a launch angle of 45 degrees since that gives out the
maximum range for given initial speed. Also assuming that it was launched at
ground level since no initial height was given. Using g = 9.8 m/s^2, the
initial velocity is calculated using the formula:
(v sinθ)^2 = (v0 sinθ)^2
– 2 g d
where v is final
velocity = 0 at the peak, v0 is the initial velocity, d is distance = 11 m
Rearranging to find for
v0: <span>
v0 = sqrt (d * g/ sin(2 θ)) </span>
<span>v0 = 10.383 m/s</span>
Answer:
time of flight of a pulse, and these most often
involve triggering of the measuring oscilloscope
with the signal that generates the sound pulse and
timing the time delay of the pulse picked up by a
conveniently placed microphone45
. Loren Winters
has reported a method similar in principle to the
present one, but which uses a completely different
detection system6
.
Explanation:
Answer:
yes; yes
Explanation:
Phases of the moon refers to the shapes of the moon due to the lit part of it visible from the Earth. On a new moon day, the moon comes between the sun and the earth such that the lit portion is not visible from the Earth. On a full moon day, the earth comes between the sun and the moon and the whole lit part is visible.
When one would view the earth from the moon, the earth would also be visible as going through the phases. The order would be reversed. Understand this with the following example, On a new moon day, the Earth would be visible completely lit from the moon. So it will be full Earth day on the moon. On a full moon day, the lit side of the Earth would be completely away and hence, from the moon, new earth would be there.
Answer:
The distance from the positive plate at which the two pass each other is 0.0023 cm.
Explanation:
We need to find the acceleration of each particle first. Let's use the electric force equation.
<u>For the proton</u>
<u>For the electron</u>
Now we know that the plate separation is 4.26 cm or 0.0426 m. The travel distance of the proton plus the travel distance of the electron is 0.0426 m.
Both of them have an initial speed equal to zero. So we have:
With this time we can find the distance from the positive plate (x(p)).
Therefore, the distance from the positive plate at which the two pass each other is 0.0023 cm.
I hope it helps you!
