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BaLLatris [955]
3 years ago
15

The distance between two cities is 144km,it takes me 3hours to travel between these cities.What speed did I travel at?​

Physics
1 answer:
Alex787 [66]3 years ago
4 0

Answer: 48 km/hr

Explanation:

speed= distance/time

144/3

=48 km/hr

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What is the acceleration of a 50 kg object pushed with a net force of 500 newtons?
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Using the formula F=ma
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during convection, hot material _____ (expands & sinks, cools & rises, expands & rises, deflates & rises) then m
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Answer:

During convection, hot material expands & rises then moves to the side and cools & sinks. this circular pattern is called a convection current.

Explanation:

Convection is one of the three methods of transfer of heat. It occurs only in fluids (liquids or gases).

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3 years ago
Read 2 more answers
How do you think that changing the mass of the pendulum bob will affect the period of the pendulum swing?​
myrzilka [38]
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5 0
3 years ago
One end of a 34-m unstretchable rope is tied to a tree; the other end is tied to a car stuck in the mud. The motorist pulls side
anyanavicka [17]

Answer:

Fc = 89.67N

Explanation:

Since the rope is unstretchable, the total length will always be 34m.

From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:

L1+L2=34m

L1^2=L2^2=L^2=2^2+(H/2)^2  Replacing this value in the previous equation:

\sqrt{2^2+H^2/4}+ \sqrt{2^2+H^2/4}=34  Solving for H:

H=\sqrt{52}

We can now, calculate the angle between L1 and the 2m segment:

\alpha = atan(\frac{H/2}{2})=60.98°

If we make a sum of forces in the midpoint of the rope we get:

-2*T*cos(\alpha ) + F = 0  where T is the tension on the rope and F is the exerted force of 87N.

Solving for T, we get the tension on the rope which is equal to the force exerted on the car:

T=Fc=\frac{F}{2*cos(\alpha) } = 89.67N

7 0
3 years ago
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