Answer:
The person above me is right i had a test a couple of days ago and thats kinda what u put and got it right!
Acceleration = (velocity final-velocity initial)/ time
where
velocity final = 135 km/hr x 1 hr /3600 s x 1000m/1km
= 37.5 m/s
velocity initial = 35 km/hr x 1hr /3600 s x 1000 m/1 km
= 9.72 m/s
a) acceleration = 2.646 m/s^2
b) acceleration in g units = (2.646m/s^2)/(9.8m/s^2)
= 0.27 units
Yes, that's right. It's the 'Planck' length, not the 'Planet' length.
You could easily find these with a web search. But in gratitude
for the bountiful 5 points, I've saved you the trouble.
AND guess what ! By doing that, I learned something, and
you didn't.
Speed of light (c): 299,792,458 meters per second
Gravitational constant (G): 6.67 x 10⁻¹¹ newton-meter²/kilogram²
Planck's Konstant (h): 6.63 x 10⁻³⁴ joule-second
Planck Length: 1.6 x 10⁻³⁵ meter
(about 10⁻²⁰ the size of a proton)
Planck Time: 10⁻⁴³ second
(about the time it takes to travel
a Planck Length at the speed of light)
Answer:
1.117935:1
Explanation:
Since the wires are of the same material, they will have the same resistivity
.
The cross-sectional area of the of a wire is given by;

where d is the diameter of the wire.
Also, the relationship between resistance R, cross-sectional area A and length l of a wire is given as follows;

Since the resistivity same for both wires, say wire 1 and wire 2, we can wreite the following;

Hence from eqaution (3), the ration of wire 1 to 2 is expressed as;

Given;


We then use equation (1) to fine the ratio of the area
to 
bearing in mind that 
This ratio gives 0.8281. Substituting this into equation (5), we get the following;
