Answer:
(a) The speed of the target proton after the collision is:
, and (b) the speed of the projectile proton after the collision is: 
.
Explanation:
We need to apply at the system the conservation of the linear momentum on both directions x and y, and we get for the x axle:
, and y axle:
. Now replacing the value given as: 
, 
for the projectile proton and according to the problem 
are perpendicular so 
, and assuming that 
, we get for x axle:
and y axle: 
, then solving for 
, we get:
and replacing at the first equation we get:
, now solving for 
, we can find the speed of the projectile proton after the collision as: and 
, that is the speed of the target proton after the collision.
Answer:
Explanation:
Acceleration is equal to the change in velocity over the change in time, or
where the change in velocity is final velocity minus initial velocity. Filling in:
Note that I made the backward velocity negative so the forward velocity in our answer will be positive.
Simplifying that gives us:
and then isolating the final velocity, our unknown:
3.0(6.0) = v + 3.0 and
3.0(6.0) - 3.0 = v and
18 - 3.0 = v so
15 m/s = v and because this answer is positive, that means that the car is no longer rolling backwards (which was negative) but is now moving forward.
Answer:
The second one
Explanation:
The second one is joining so it is the one which belongs to X, first one belongs to Z
Explanation:
1. draught
2. Parallax error
3. angle if displacement
4. air resistance or any form of obstruction
The answer is 36 kilometers per hour, or 10 meters per second.
