1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ad libitum [116K]
2 years ago
7

A 0.05 kg arrow is fired at a velocity towards a 1.2 kg apple. The arrow sticks in the apple and both move at 3.6

Physics
1 answer:
ivanzaharov [21]2 years ago
3 0

We have that the  initial velocity   is mathematically given as

V1=86.4m/s

<h3>Velocity</h3>

Question Parameters:

  • A 0.05 kg arrow
  • Is fired at a velocity towards a 1.2 kg apple.
  • The arrow sticks in the apple and both move at 3.6m/s.

Generally the equation for the Conservation of momentum   is mathematically given as

M1V1=M2V2

Therefore

0.05*V1=1.2*3.6

V1=(1.2*3.6)/0.05

V1=86.4m/s

For more information on Velocity visit

brainly.com/question/7359669

You might be interested in
A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches
tiny-mole [99]

Answer:

26.8 seconds

Explanation:

To solve this problem we have to use 2 kinematics equations: *I can't use subscripts for some reason on here so I am going to use these variables:

v = final velocity

z = initial velocity

x = distance

t = time

a = acceleration

{v}^{2}  =  {z}^{2}  + 2ax

v = z + at

First let's find the final velocity the plane will have at the end of the runway using the first equation:

{v}^{2}  =  {0}^{2}  + 2(5)(1800)

v = 60 \sqrt{5}

Now we can plug this into the second equation to find t:

60 \sqrt{5}  = 0 + 5t

t = 12 \sqrt{5}

Then using 3 significant figures we round to 26.8 seconds

3 0
3 years ago
A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.
MakcuM [25]

Answer:

b. 9.5°C

Explanation:

m_i = Mass of ice = 50 g

T_i = Initial temperature of water and Aluminum = 30°C

L_f = Latent heat of fusion = 3.33\times 10^5\ J/kg^{\circ}C

m_w = Mass of water = 200 g

c_w = Specific heat of water = 4186 J/kg⋅°C

m_{Al} = Mass of Aluminum = 80 g

c_{Al} = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C

The final equilibrium temperature is 9.50022°C

4 0
3 years ago
A dipole of moment 0.5 e·nm is placed in a uniform electric field with a magnitude of 8 times 104 N/C. What is the magnitude of
Over [174]

Answer:

The net torque is zero

Explanation:

Let's assume that the dipole is compose of two equal but oposite charges e, and it cam be represented by a rod with one end having a charge e and the other end with a charge of -e. Notice that the dipole is parallel to the electric field thus the force felt by both of the charges will be parallel to the electric field. This means that there will be no components of the forces that are perpendicular to the rod which is a requirement for it to have a torque.

8 0
3 years ago
At a certain instant a particle is moving in the +x direction with momentum +8 kg m/s. During the next 0.13 seconds a constant f
jeka94

Answer:

The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s

Explanation:

The momentum of the particle is related to force by the following equation:

Δp = F · Δt

Where:

Δp =  change in momentum = final momentum - initial momentum

F = constant force.

Δt = time interval.

Let´s calculate the x-component of the momentum after the 0.13 s:

final momentum - 8 kg m/s = -7 N · 0.13 s

final momentum = -7 kg m/s² · 0.13 s + 8 kg m/s

final momentum = 7.09 kg m/s

Now let´s calculate the y-component of the momentum vector after the 0.13 s. Since the particle wasn´t moving in the y-direction, the initial momentum in this direction is zero:

final momentum = 5 kg m/s² · 0.13 s

final momentum = 0.65 kg m/s

Then, the mometum vector will be as follows:

p = (7.09 kg m/s,  0.65 kg m/s)

The magnitude of this vector is calculated as follows:

|p| = \sqrt{(7.09 kg m/s)^{2} + (0.65 kg m/s)^{2}} = 7.12 kg m/s

The momentum of the particle at the end of the 0.13 s time interval is 7.12 kg m/s

4 0
3 years ago
Charlotte throws a paper airplane into the air, and it lands on the ground. Which best explains why this is an example of projec
lubasha [3.4K]

Explanation:

  1. yes it is the force that is subjected by the force of gravity only

4 0
3 years ago
Read 2 more answers
Other questions:
  • A stone is thrown vertically upward with a speed of 18 m/s. (a) How long does it take the stone to reach a height of 11 m? (b) h
    10·1 answer
  • The wheel of a car has a radius of 0.413 m. If the wheel rotates at 456 revolutions per minute, what is the speed (in m/s) at wh
    11·2 answers
  • A 115-turn circular coil of radius 2.71 cm is immersed in a uniform magnetic field that is perpendicular to the plane of the coi
    9·1 answer
  • Find τf, the torque about point p due to the force applied by the achilles' tendon.
    11·1 answer
  • A student has a displacement of 304 m north in 180 s. What was the student's average velocity?
    15·1 answer
  • ASAP I’m timed on this so help would really be appreciated :)
    9·1 answer
  • A.
    13·1 answer
  • Calcula la dilatación volumétrica de una solución de glicerina que tiene un volumen inicial de 16 litros a 20⁰C y se calienta a
    6·1 answer
  • What is the role of friction when ; a boats engine stops
    6·1 answer
  • Silicon (chemical symbol Si) is located in Group 14, Period 3. Which is silicon
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!