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arsen [322]
4 years ago
12

A glycosidic bond can join two monosaccharide molecules to form a disaccharide.(T/F)

Chemistry
1 answer:
Dafna1 [17]4 years ago
3 0

Answer:

True

Explanation:

A disaccharide is a sugar and the general molecular formula of a disaccharide is C₁₂H₂₂O₁₁.

A disaccharide is formed when two monosachharide units are joined by a covalent bond called the glycosidic bond.

The glycosidic bond in a disaccharide is formed by dehydration reaction between the two monosachharide units. The removal of the water molecule results in the formation of the glycosidic linkage.

For example: maltose a disaccharide, is formed when two molecules of glucose are joined by a (1→4) glycosidic bond. As, the glycosidic bond is formed between the carbon 1 of one glucose unit and carbon 4 of another glucose unit.

Therefore, in a disaccharide the two monosaccharide units are joined by a glycosidic bond or linkage.

Therefore, the given statement is TRUE.

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Answer:

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Explanation:

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Lady_Fox [76]

Explanation:

(a)  The given data is as follows.  

         Load applied (P) = 1000 kg

         Indentation produced (d) = 2.50 mm

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Expression for Brinell Hardness is as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}    

Now, putting the given values into the above formula as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}                            = \frac{2 \times 1000 kg}{3.14 \times 10 mm [D - \sqrt{((10 mm)^{2} - (2.50)^{2})}]}  

                       = \frac{2000}{9.98}                          

                       = 200

Therefore, the Brinell HArdness is 200.

(b)     The given data is as follows.

               Brinell Hardness = 300

                Load (P) = 500 kg

               BHI diameter (D) = 10 mm

             Indentation produced (d) = ?

                      d = \sqrt{(D^{2} - [D - \frac{2P}{HB} \pi D]^{2})}

                         = \sqrt{(10 mm)^{2} - [10 mm - \frac{2 \times 500 kg}{300 \times 3.14 \times 10 mm}]^{2}}

                          = 4.46 mm

Hence, the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used is 4.46 mm.

5 0
3 years ago
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If an object moves in uniform circular motion in a circle of radius R=2.00 meters, and the object takes 5.00 seconds to
Minchanka [31]

Answer:

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Explanation:

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It takes 5 seconds to complete 10 revolutions. It means its angular velocity is :

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So, the centripetal acceleration of the object is 315.5\ m/s^2.

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