Yet and 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Answer:
KO is the limiting reactant.
0.11 mol O₂ will be produced.
Explanation:
4 KO₂ + 2 H₂O ⇒ 4 KOH + 3 O₂
Find the limiting reagent by dividing the moles of the reactant by the coefficient in the equation.
(0.15 mol KO₂)/4 = 0.0375
(0.10 mol H₂O)/2 = 0.05
KO₂ is the limiting reagent.
The amount of product produced depends on the limiting reagent. To find how much is produced, take moles of limiting reagent and multiply it by the ratio of reagent to product. You can find the ratio by looking at the equation. For every 4 moles of KO₂, 3 moles of O₂ are produced.
0.15 mol KO₂ (3 mol O₂)/(4 mol KO₂) = 0.1125 mol O₂
0.11 mol O are produced.
Answer:
I <u>think</u> your answer is: C. ("An Arrhenius acid increases [H +] in the solution.")
Explanation:
An Arrhenius acid is a substance that dissociates in water to form hydrogen ions (H + ); that is, an acid increases the concentration of H + ions in an aqueous solution. This causes the protonation of water, or the creation of the hydronium (H 3 O +) ion.
Hopefully this helps!
Have a great day! ^^
A large number in front of a compound designates how many units there are of that compound. Parentheses can be used to designate a special structure, where other molecules are attached to the larger, complex molecule.
The answer would be 1,3,1,3
