What tool would you use to compare the mass of two objects
2 answers:
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Answer:
Hi, the question is incomplete. However, the question is about the calculation of volume of a product when the volume of one of the reactants is provided.
9.587 cm^3
Explanation:
The balanced equation for the chemical reaction is shown below:
⇒
In the chemical reaction above, 2 moles of water produced 4 moles of hydrogen fluoride. If 4.8 cm^3 of water were consumed, we can calculated the volume of hydrogen fluoride that would be produced as follow:
Using STP, 1 mole of gas has a volume of 22.4 L
Thus, 4.8 cm^3 = 0.0048 L is equivalent to 2.14*10^-4
since 2 moles of water produced 4 moles of hydrogen fluoride, therefore, 2.14*10^-4 would produced 2*2.14*10^-4 = 4.28*10^-4 moles
we can convert the moles to L by multiplying with 22.4
volume of hydrogen fluoride = 4.28*10^-4 * 22.4 = 0.009587 L = 9.587 cm^3
Answer:
Explanation:
Hi there,
To get started, let's first observe our rate law:
we typically use square brackets [x] for chemistry kinetics, because they specifically tell us we are dealing with <em>concentrations</em>.
This rate law is in fourth-order, because the concentrations powers add up to 4. We are not told the unit of time for this prompt (unless you know it), so I just assumed the time unit to be "time."
To calculate the reaction rate, we simply plug in the concentration of A and B into the rate law. k is the <em>rate constant</em> and stays the same for an individual reaction.
Thus, the rate of reaction with those concentrations is 0.4 M/time.
Notice, the rate constant does in fact have units of it own. The unit for k can be calculated by knowing that:
- Rate (R) must end up with units of concentration (M) per time.
- The concentrations raised to a power can be used to help solve for the units of k.
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