Answer:
K2CO3(aq) + H2O(l)
Explanation:
Balance the equation
2KOH(aq) + CO2(g) ------ K2CO3(aq) + H2O(l)
Answer:
87.3 calories of heat is required.
Explanation:
Heat = mcΔT
m= mass, c = specific heat of silver, T = temperature
H= 57.8 g * 0.057 cal/g°C * ( 43.5 - 17 °C)
H = 57.8 * 0.057 * 26.5
H = 87.3069 cal.
The heat required to raise the temperature of 57.8 g of silver from 17 °C to 43.5 °C is 87.3 calories.
Answer:
There are a number of possibilities for the answer to this question, so I will address a few only:
Explanation:
1. Many ionic substances will dissolve completely in water to form an aqueous solution of cations and anions; this solution will conduct electricity.
2. The substance will have a slightly lower melting point than a mid-level covalent network solid.
3. The substance will certainly not conduct electricity as a solid.
I would wager a guess that you're talking about microlattice.
Fe(s)+Ca(NO₃)₂(aq)⇒no reaction
<h3>Further explanation</h3>
In voltaic series
Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au
The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent
The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent
So that the element located on the left can push the element on the right in the redox reaction
Reaction
Fe(s)+Ca(NO₃)₂(aq)⇒no reaction
Fe cannot reduce Ca because Ca is more reactive, so the reaction does not occur
On the contrary, this reaction can occur
3Ca(s) + 2Fe(NO₃)₃(aq) = 3Ca(NO₃)₂(aq) + 2Fe(s)
