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kiruha [24]
3 years ago
7

Can anyone help with this?

Chemistry
1 answer:
8090 [49]3 years ago
3 0
Yes what is it..we can help you
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A steel tank contains carbon dioxide at a pressure of 13.0 atm when the temperature is 34oC. What will be the internal gas press
morpeh [17]

Answer:

D. 15.8atm

Explanation:

Given parameters:

Initial pressure = 13atm

Initial temperature  = 34°C = 34 + 273  = 307K

Final temperature  = 100°C = 100 + 273  = 373K

Unknown:

Final pressure  = ?

Solution:

To solve this problem, we apply a derivation of the combined gas law taking the volume as a constant.

The expression is shown mathematically below;

        \frac{P_{1} }{T_{1} }   = \frac{P_{2} }{T_{2} }

P and T pressure and temperature values

1 and 2 are initial and final states

 Insert the parameters and solve for T₂;

    \frac{13}{307}   = \frac{P_{2} }{373}  

        P₂  = 15.8atm

4 0
3 years ago
For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
Diano4ka-milaya [45]
The balanced chemical reaction is given as follows:

<span>2 KClO3(s) → 2 KCl(s) + 3 O2(g)

The starting amount of the reactant are given above. These values would be used for the calculations. We do as follows:

</span>2.72 g KClO3 (1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 1.06 g O2
<span>
0.361 g KClO3 </span>(1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 0.14 g O2
<span>
83.6 kg KClO3 (1000g / 1kg) </span>(1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 3275.76 g O2
<span>
22.5 mg KClO3</span> (1 g / 1000 mg) (1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 0.009 g O2
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The answer is A. you sre correct!
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I think it’s salt water
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Is a potential to provide effective treatment with fewer side effects than a traditional therapy.

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