Explanation:
Solution:
Let the time be
t1=35min = 0.58min
t2=10min=0.166min
t3=45min= 0.75min
t4=35min= 0.58min
let the velocities be
v1=100km/h
v2=55km/h
v3=35km/h
a. Determine the average speed for the trip. km/h
first we have to solve for the distance
S=s1+s2+s3
S= v1t1+v2t2+v3t3
S= 100*0.58+55*0.166+35*0.75
S=58+9.13+26.25
S=93.38km
V=S/t1+t2+t3+t4
V=93.38/0.58+0.166+0.75+0.58
V=93.38/2.076
V=44.98km/h
b. the distance is 93.38km
Kinetic energy is the energy for a catapult.
The waste that poses substantial or potential threats to public and environment health
Hazardous waste are actually defined as RCRA in 40 CFR 261 the the four hazardous traits are
ignitability
reactivity
corrosivity
toxicity
i think its b
If the object being represented is going both up and to the right.
Answer:
it would be c, there are fewer atoms in the reactants than in the products, and the total mass is less in the reactants than in the products.
Explanation:
