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zubka84 [21]
3 years ago
7

Animal-vehicle collisions can happen any time of the year, but_______ is the peak season for deer- car collisions.

Physics
2 answers:
Dovator [93]3 years ago
7 0

Answer:

A. Autumn

Explanation:

Autumn is when all deer starts roaming around and causing car collisions.

Murrr4er [49]3 years ago
3 0

Answer:

A

Explanation:

that's migrating season

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A pendulum of mass 5.0 kg hangs in equilibrium. A frustrated student walks up to it and kicks the bob with a horizontal force of
Phoenix [80]

Answer:

The length is L = 6.206m and the angle is \theta = 37.752^o.

Explanation:

The period T of the pendulum is related to its length L by

T = 2\pi \sqrt{\dfrac{L}{g} },

where g =9.8m/s^2 is the acceleration due to gravity.

Solving for L we get

L = \dfrac{T^2g}{4\pi^2}

putting in T =5.0s and g =9.8m/s^2 we get:

L = \dfrac{(5.0s)^2*9.8m/s^2}{4\pi^2}

\boxed{L = 6.206m.}

There are two forces acting on the pendulum: The gravitational force mg and the F = 30N student's force. Therefore, the angular displacement \theta that these forces give is

sin(\theta ) = \dfrac{F}{mg}

\theta = sin^{-1}( \dfrac{F}{mg})

putting in F =30N, m =5.0kg, and g =9.8m/s^2 we get

\theta = sin^{-1}( \dfrac{30N}{5.0kg*9.8m/s^2})

\boxed{\theta = 37.752^o.}

4 0
3 years ago
A 9­v battery is connected to a light bulb with a resistance of 3?. what is the current in the circuit
anygoal [31]
9/3= 3 ampere.. that would be the aswer
7 0
3 years ago
Transverse waves are sent along a 5.00-m-long string with a speed of 30.00 m/s. The string is under a tension of 10.00 N. What i
Kipish [7]

Answer:

0.055 kg

Explanation:

Given that

Length of the string, l = 5 m

Speed of the wave, v = 30 m/s

Tension on the string, F(t) = 10N

From the formula written in the attachment, we have

v = velocity of the wave, in m/s

F(t) = Tension on the string, in N

U = Mass per length of the string, in kg/m

m = Mass of the string, in kg

l = Length of the string, in m

See attachment for the calculation

3 0
3 years ago
If all else stays the same, which would cause an increase in the gravitational force on a space shuttle?
Alenkasestr [34]

Answer: Decreasing the distance of the space shuttle from Earth .

Explanation:

According to expression of gravitational force:

F=\frac{G\times m_1\times m_2}{r^2}

G = gravitational constant

m_1, m_2 = masses of two objects

r = Distance between the two objects.

F = Gravitational force

From the above expression we can say that gravitational force is inversely proportional to squared of the distance between the two masses.

F\propto \frac{1}{r^2}

So, in order to increase the gravitational force on space shuttle distance between the space space shuttle  must be decreased.

Hence, the correct answer 'decreasing the distance of the space shuttle from Earth '.

8 0
3 years ago
Read 2 more answers
When an object is lifted against the force of gravity it has gravitational potential energy. The energy depends on the object's
USPshnik [31]
The answer is actually True, I just took the test and it was correct.
5 0
3 years ago
Read 2 more answers
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