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-BARSIC- [3]
3 years ago
13

What are possible units for impulse? Check all that apply.

Physics
2 answers:
Neporo4naja [7]3 years ago
6 0

Units of impulse: N • s, kg • meters per second

Explanation:

Impulse is defined in two ways:

1)

Impulse is defined as the product between the force exerted in a collision and the duration of the collision:

I=F\Delta t

where

F is the force

\Delta t is the time interval

Since the force is measured in Newtons (N) and the time is measured in seconds (s), the units for the impulse are

[I] = [N][s]

So,

N • s

2)

Impulse is also defined as the change in momentum experienced by an object:

I=\Delta p

where the change in momentum is given by

\Delta p = m\Delta v

where m is the mass and \Delta v is the change in velocity.

The mass is measured in kilograms (kg) while the change in velocity is measured in metres per second (m/s), therefore the units for impulse are

[I]=[kg][m/s]

so,

kg • meters per second

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

TEA [102]3 years ago
6 0

Answer:

B

Explanation:

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Maximum voltage produced in an AC generator completing 60 cycles in 30 sec is 250V. (a) What is period of armature? (b) How many
Vlada [557]

Answer:

a. 2 Hz b. 0.5 cycles c . 0 V

Explanation:

a. What is period of armature?

Since it takes the armature 30 seconds to complete 60 cycles, and frequency f = number of cycles/ time = 60 cycles/ 30 s = 2 cycles/ s = 2 Hz

b. How many cycles are completed in T/2 sec?

The period, T = 1/f = 1/2 Hz = 0.5 s.

So, it takes 0.5 s to complete 1 cycles. At t = T/2 = 0.5/2 = 0.25 s,

Since it takes 0.5 s to complete 1 cycle, then the number of cycles it completes in 0.25 s is 0.25/0.5 = 0.5 cycles.

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E = E₀ × 0 = 0

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8 0
2 years ago
A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s .
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Answer:

Force exerted, F = 1.5 N

Explanation:

It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.

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We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :

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So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.

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