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3 years ago

Discuss the correlation or connection between stars with a higher mass and the amount of fuel they have to work with

Physics

1 answer:

dimulka [17.4K]3 years ago

3 0

Larger stars have a higher amount of fuel in order to keep the process of nuclear fusion going.

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What best describes electrons

lyudmila [28]

Answer: A negatively charged particle that is found in atoms.

4 0

3 years ago

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a s

DedPeter [7]

Complete Question

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a small patch of light on the far wall. Having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. It appears that the central maximum is about 2 cm across, and you estimate that the distance from the window shade to the wall is about 5 m.

Required:

Estimate the diameter of the pinhole.

Answer:

The diameter is $d =0.000336 m$

Explanation:

From the question we are told that

The central maxima is $D= 2cm = \frac{2}{100} = 0.02m$

The distance from the window shade is $L = 5m$

The average wavelength of the sun is mathematically evaluated as

$\lambda_{ave } = \frac{\lambda_i + \lambda_f}{2}$

Generally the visible light spectrum has a wavelength range between 400 nm to 700 nm

So the initial wavelength of the sun is $\lambda _i = 400nm$

and the final wavelength is $\lambda_f = 700nm$

Substituting this into the above equation

$\lambda_{sun} = \frac{400nm +700nm}{2}$

$= 550nm$

The diameter is evaluated as

$d = \frac{2.44 \lambda_{sun} L}{D}$

substituting values

$d = \frac{2.44 * 550*10^{-9} * 5 }{0.02}$

$d =0.000336 m$

5 0

3 years ago

How to find a planet’s gravitational field strength using its radius?

grin007 [14]

The gravitational field strength is approximately equal to 10 N.

<u>Explanation:</u>

Gravitational field strength is the measure of gravitational force acting on any object placed on the surface of the planet. Generally, the mass of the object is considered as 1 kg.

So the gravitational field strength will be equal to the gravitational force acting on the object.

The formula for gravitational field strength is

$g = \frac{F}{m}$

Here g is the gravitational field strength, m is the mass of the object placed on the surface and F is the gravitational force acting on the object.

Since, the mass of any object placed on the surface of earth will be negligible compared to the mass of Earth, so the mass of the object is considered as 1 kg.

Then the g = F

And $F =\frac{GMm}{r^{2} }$

Here G is the gravitational constant, M is the mass of Earth and m is the mass of the object placed on the surface, while r is the radius of the Earth.

$g = F = \frac{6 \times 10^{24} \times 6.67 \times 10^{-11} \times 1}{(6.6 \times 10^{6}) ^{2} }$