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Marina CMI [18]
3 years ago
12

What is the area of this figure use 3.14 for pi

Mathematics
2 answers:
DochEvi [55]3 years ago
5 0

Answer:

Area of the figure is 22.28ft²

Step-by-step explanation:

The figure is made up of a semicircle and a square.

The area of the figure = area of semicircle + area of square

Area of square L² where

L is length of the square = 4² = 16ft²

Area of a semicircle = πr²/2

The radius of the semicircle = 4/2 = 2ft

Area of semicircle = π(2)²/2

Area of semicircle = 4π/2

Area of the semicircle = 2πft² = 6.28ft²

Area of the figure = 16ft + 6.28ft²

Area of the figure = 22.28ft²

umka2103 [35]3 years ago
3 0
Area of a square is a².

4² = 16

Now find the area of the semicircle.

(πr²)/2
(3.14)(2)²/2
12.56/2
6.28

Now add the areas to find the total area.

6.28 + 16 = 22.28

Hope this helps :)
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Pls help (kinda easy)
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Answer:

f(x)=(2x+1)(2x-1).

Step-by-step explanation:

We want to convert the function into the form that let's us easily find the x-intercept, and it would be for the form (ax+b)(cx+d) because then we can find the x-intercept in the following manner:

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We factor our function f(x)=4x^2-1 and get

\boxed{f(x)=(2x+1)(2x-1)}

Now this form let's us easily find the x-intercepts:

x=-1/2

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and so we pick the second choice: f(x)=(2x+1)(2x-1).

5 0
3 years ago
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A bag of numbered lottery balls contains the numbers 1 through 40. What is the probability that a randomly selected ball will be
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Answer:

3/40

Step-by-step explanation:

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Preliminary data analyses indicate that it is reasonable to use a t-test to carry out the specified hypothesis test. Perform the
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<h2>Answer with explanation:</h2>

By considering the given information, we have

Null hypothesis : H_0: \mu=35.0

Alternative hypothesis : H_1: \mu\neq35.0

Since the alternative hypothesis is two-tailed , so the test is a two-tailed test.

Given : Sample size : n= 20, since sample size is less than 30 so the test applied is a t-test.

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Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

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Significance level = 0.01

For two tailed,  Significance level =\dfrac{0.01}{2}=0.005

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