A third-class lever increases the distance a load can be moved. True False

5/8 ≠ (3/4 + 1/16) because 5/8 < 3/4 EXPLAIN THIS PROBLEM AND WHAT IT MEANS

balu736 [363]

5/8 = 3/4+1/16 is false because, the final values compared on each side of equation is not the same

- 5/8 = 0.625
- 3/4+1/16 = 0.8125

0.625 = 0.8125, it is not equal but less than

8 0

3 years ago

Triangles triangle ABC and triangle DEF are similar. Find the angles of these triangles if Mesurements of angle A=100 degrees, a

beks73 [17]

Answer:

<D = 100

<E =30

<F =50

Step-by-step explanation

Given that triangles triangle ABC and triangle DEF are similar, this means that their angles are congruent i.e

<A = <D

<B = <E

<C = <F

Given

<A = 100 then <D = 100

<B = 30°, then <E = 30°

To get <F, we will use the expression

<D+<E+<F = 180 (sum of angles in a triangle is 180°)

100+30+<F = 180

130+<F = 180

<F = 180-130

<F = 50°

Hence the measure of <F is 50°

3 0

2 years ago

10. Two lighthouses are located on a north-south line.

Kamila [148]

The question is an illustration of bearing (i.e. angles) and distance (i.e. lengths)

The distance between both lighthouses is 5783.96 m

I've added an attachment that represents the scenario.

From the attachment, we have:

$\mathbf{\angle A = 180^o - 120^o\ 43'}$

Convert to degrees

$\mathbf{\angle A = 180^o - (120^o +\frac{43}{60}^o)}$

$\mathbf{\angle A = 180^o - (120^o +0.717^o)}$

$\mathbf{\angle A = 180^o - (120.717^o)}$

$\mathbf{\angle A = 59.283^o}$

$\mathbf{\angle B = 39^o43'}$

Convert to degrees

$\mathbf{\angle B = 39^o + \frac{43}{60}^o}$

$\mathbf{\angle B = 39^o + 0.717^o}$

$\mathbf{\angle B = 39.717^o}$

So, the measure of angle S is:

$\mathbf{\angle S = 180 - \angle A - \angle B}$ ---- Sum of angles in a triangle

$\mathbf{\angle S = 180 - 59.283 - 39.717}$

$\mathbf{\angle S = 81}$

The required distance is distance AB

This is calculated using the following sine formula:

$\mathbf{\frac{AB}{\sin(S)} = \frac{AS}{\sin(B)} }$

Where:

$\mathbf{AS = 3742}$

So, we have:

$\mathbf{\frac{AB}{\sin(81)} = \frac{3742}{\sin(39.717)}}$

Make AB the subject

$\mathbf{AB= \frac{3742}{\sin(39.717)} \times \sin(81)}$

$\mathbf{AB= 5783.96}$

Hence, the distance between both lighthouses is 5783.96 m

Read more about bearing and distance at:

brainly.com/question/19017345

5 0

1 year ago

I need help...cause i’m confused

Arisa [49]

the answer is d thats what im choosing because i recall doing a similar problem to this

6 0

3 years ago

Find the slope of the line.

Archy [21]

Answer:

$\displaystyle m=0.8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (4, 1.2)

Point (10, 6)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute [SF]: $\displaystyle m=\frac{6-1.2}{10-4}$
Subtract: $\displaystyle m=\frac{4.8}{6}$
Divide: $\displaystyle m=0.8$

7 0

2 years ago

Read 2 more answers