The object should be placed 20/cm from the lens so as to form its real image on the screen
<h3>Mirror equation</h3>
The mirror equation is given according to the expression below;
1/f = 1/u + 1/v
where
f is the focal length
u is the object distance
v is the image distance
Given the following parameters
f = 5cm
v = 20cm
Required
object distance u
Substitute
1/5 = 1/u +1/20
1/u = 1/5-1/20
1/u = 3/20
u = 20/3 cm
Hence the object should be placed 20/cm from the lens so as to form its real image on the screen
Learn more on mirror equation here; brainly.com/question/27924393
#SPJ1
Given that:
The triangle ABC and its image are shown below.
Step-by-step explanation:
In the below figure triangle A'B'C' is the image of triangle ABC.
We need to sketch a possible line that triangle ABC could translate along to create its image.
So, connect the corresponding vertices. So, the required lines are AA', BB' and CC '.
In translation, each point of the figure is shifted from point to another point in a particular distance and direction.
Point A, B and C are shifted to A' B' and C' respectively. So AA', BB' and CC' represents the distance and direction of translation.
From the figure it is clear that triangle ABC shifted 10 units right and 6 units down.
Answer:
Letter B.
Step-by-step explanation:
.....................................
Just multiply across:
3 x 5 = 15
8 x 6 = 48
15/48 = 5/16
hope this helps :)
The scale factor is 0.75 or 3/4
TR/EZ=9/12=3/4