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3 years ago

Multiply 8 times the square root of 3 by 9 times the square root of 27.

Mathematics

1 answer:

Viktor [21]3 years ago

6 0

8√3 · 9√27
8 · 9 ·√3 · √27
72 · √81
72 · 9
648

The answer is 648. :)

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How to do the problem

charle [14.2K]

Answer:

the answer is 10n-13

Step-by-step explanation:

this is a one step problem, all you need to do is add all the like terms together such as n and 9n and since they are both positives they add up to 10n and then with -10 and -3 they would add together to make -13. thats all there is to it, the answer is 10n-13

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3 years ago

Read 2 more answers

What square root is closest to 5

nikklg [1K]

Answer: 2.236

Step-by-step explanation: The square root of 5 is expressed as √5 in the radical form and as (5)½ or (5)0.5 in the exponent form. The square root of 5 rounded up to 5 decimal places is 2.23607. It is the positive solution of the equation x2 = 5.

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3 years ago

-2x + y = 4

nirvana33 [79]

Answer:

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Step-by-step explanation:

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3 years ago

Juliette made cookies for a bake sale and wants to package the same number of cookies together. If she makes 16 chocolate chip c

pentagon [3]

Answer:

8 cookies

Step-by-step explanation:

We are asked in the above question to find the most number of cookies that would be in the bag.

We solve the above question using the Greatest Common Factor method

We find the factors of 16, 24, 32

The factors of 16 are: 1, 2, 4, 8, 16

The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24

The factors of 32 are: 1, 2, 4, 8, 16, 32

Then the greatest common factor is 8.

Therefore, the most number of each type of cookie that will be in the bag is 8 cookies

4 0

3 years ago

The sum of four consecutive odd integers is three more than five times the least of the integers. Find the integers.

Olegator [25]

Answer:

Step-by-step explanation:

{k - some integer}

2k+1 - the first odd integer (the least)

5(2k+1) - five times the least

5(2k+1)+3 -<u> three more than five times the least</u>

2k+1+2 = 2k+3 - the odd integer consecutive to 2k+1

2k+3+2 = 2k+5 - the next odd consecutive integer (third)

2k+5+2 = 2k+7 - the last odd consecutive integer (fourth)

2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>

2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3

8k + 16 = 10k + 5 + 3

- 10k -10k

-2k + 16 = 8

-16 - 16

-2k = -8

÷(-2) ÷(-2)

k = 4

2k+1 = 2•4+1 = 9

2k+3 = 2•4+3 = 11

2k+5 = 2•4+5 = 13

2k+7 = 2•4+7 = 15

Check: 9+11+13+15 = 48; 48-3 = 45; 45:5 = 9 = 2k+1

4 0

3 years ago