I have one cookie. A minute later I want to eat a cookie. That's one cookie plus a negative one cookie. At the end, I have no cookie left.
Let the difference between consecutive terms be D. If the middle term is 30, then the term before it is 30-D, and the term after it is 30+D. So the sum of these three terms would be (30-D) + 30 + (30+D) = 3*30.
Extending this sum to include all 11 terms centered around 30, we see that any addition of D is canceled by a balanced subtraction, leaving you with 11 copies of 30. So the value of the sum is 11*30 = 330.
Answer:
Step-by-step explanation:
Take the log of both sides:
log(2) = t*log 1.015, so that:
log(2)
t = --------------- = 46.6 compounding periods, which is 46.6/4, or 11.6 years
log 1.015
Can't write this exponential equation as a logarithm; instead, CAN write it in logarithmic form.
Ming forgot about the decimal in front of the 24 which would be 2400/100, but .24 < 14 because 1400/100 > 24/100
Answer:
yeshhh
Step-by-step explanation:
