Answer:
C
Step-by-step explanation:
The center of inscribed circle into triangle is point of intersection of all interior angles of triangle.
The center of circumscribed circle over triabgle is point of intersection of perpendicular bisectors to the sides.
Circumscribed circle always passes through the vertices of the triangle.
Inscribed circle is always tangent to the triangle's sides.
In your case angles' bisectors and perpendicular bisectors intesect at one point, so point A is the center of inscribed circle and the center of corcumsribed circle. Thus, these circles pass through the points X, Y, Z and G, E, F, respectively.
Answer:
x ≈ 7.2
Step-by-step explanation:
Given a tangent- secant from an external point to the circle, then
the the square of the measure of the tangent is equal to the product of the external part of the secant and the entire secant, that is
x² = 4(4 + 9) = 4 × 13 = 52 ( take the square root of both sides )
x =
≈ 7.2 ( to the nearest tenth )
Answer:
We need more info, take a picture of the qustion
Step-by-step explanation:
Here, 3m is a scalar that we use to multiply each element of the matrix.
We have
![3m \left[\begin{array}{cc}-5m&2m\\6m&6n\end{array}\right]](https://tex.z-dn.net/?f=%20%203m%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-5m%262m%5C%5C6m%266n%5Cend%7Barray%7D%5Cright%5D%20)
.
We get
![\left[\begin{array}{cc}(3m)(-5m)&(3m)(2m)\\(3m)(6m)&(3m)(6n)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%283m%29%28-5m%29%26%283m%29%282m%29%5C%5C%283m%29%286m%29%26%283m%29%286n%29%5Cend%7Barray%7D%5Cright%5D%20)
which simplifies to