Answer:
9x + 7
Step-by-step explanation:
Given
6x + 5y + 3x + 7 - 5y ← collect like terms
= (6x + 3x ) + (5y - 5y ) + 7
= 9x + 0 + 7
= 9x + 7
y = - 3(x + 1 )² + 2
the equation of a quadratic in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
here vertex = (- 1, 2), hence
y = a(x + 1)² + 2
to find a substitute (1, - 10) into the equation
- 10 = 4a + 2 ⇒ 4a = - 12 ⇒ a = - 3
y = - 3(x + 1)² + 2 ← in vertex form
Answer:

Step-by-step explanation:
Two ∆s can be considered to be congruent to each other using the Side-Angle-Side Congruence Theorem, if an included angle, and two sides of a ∆ are congruent to an included angle and two corresponding sides of another ∆.
∆ABC and ∆DEF has been drawn as shown in the attachment below.
We are given that
and also
.
In order to prove that ∆ABC
∆DEF using the Side-Angle-Side Congruence Theorem, an included angle which lies between two known side must be made know in each given ∆s, which must be congruent accordingly to each other.
The included angle has been shown in the ∆s drawn in the diagram attached below.
Therefore, the additional information that would be need is:
