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sergeinik [125]
4 years ago
7

Find the value of x. Polygon angle sums

Mathematics
2 answers:
pav-90 [236]4 years ago
6 0

Answer:

x = 50

Step-by-step explanation:

In a polygon, the angles add up to 360°:

x + 10 + 2x + 3x + x = 360

7x + 10 = 360

7x = 350

x = 50

wariber [46]4 years ago
4 0

Answer:

x = 50

Step-by-step explanation:

There are 4 angles, making it a Quadrilateral. A Quadrilateral has a ∑m∠ of 360°.

Set each angle equal to 360°:

2x + 3x + x + x + 10 = 360

Simplify. Combine like terms:

(2x + 3x + x + x) + 10 = 360

7x + 10 = 360

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

PEMDAS =

Parenthesis

Exponents

Roots

Multiplication

Division

Addition

Subtraction

First, subtract 10 from both sides:

7x + 10 (-10) = 360 (-10)

7x = 360 - 10

7x = 350

Next, divide 7 from both sides:

(7x)/7 = (350)/7

x = 350/7

x = 50

50 is your value for x.

~

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Answer:

Second choice

Step-by-step explanation:

The sides of the new triangle is in proportion to a scale of 3 to the original triangle. Since the sides are in proportions, the triangles are similar. Thus the angles are the same.

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10. Write in slope-intercept form:<br> -3x + 4y = 12
Anastasy [175]

Answer:

Step-by-step explanation:

Write in slope-intercept form:

-3x + 4y = 12 is

 Slope = 1.500/2.000 = 0.750

 x-intercept = 12/-3 = 4/-1 = -4.00000

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3 years ago
Two numbers grouped together like (7, 2) are called ______.
kogti [31]
It would an ordered pair
7 0
3 years ago
Find a vector equation and parametric equations for the line segment that joins p to q.P(0, - 1, 1), Q(1/2, 1/3, 1/4)
lakkis [162]

Answer:

vector equation:

\overrightarrow{PQ}=\begin{bmatrix}1/2}\\4/3\\-3/4\end{bmatrix}

parametric equations:

r_x = \dfrac{1}{2}t\\r_y = -1 +\dfrac{4}{3}t\\r_z = 1=\dfrac{3}{4}t

Step-by-step explanation:

The coordinates of the points are given as:

P(0,-1,1) and Q(1/2,1/3,1/4)

the coordinates of any points are also position vectors (vectors starting from the origin to that point), and can be represented as:

\overrightarrow{OP} = 0\hat{i}-1\hat{j}+1\hat{k}

or

\overrightarrow{OP} = \begin{bmatrix}0\\-1\\1\end{bmatrix}

similarly,

\overrightarrow{OQ} =\dfrac{1}{2}\hat{i}+\dfrac{1}{3}\hat{j}+\dfrac{1}{4}\hat{k}

or

\overrightarrow{OQ} = \begin{bmatrix}1/2}\\1/3\\1/4\end{bmatrix}

the vector PQ can be described as:

\overrightarrow{PQ}=\overrightarrow{OQ}-\overrightarrow{OP}

\overrightarrow{PQ}=\begin{bmatrix}1/2}\\1/3\\1/4\end{bmatrix}-\begin{bmatrix}0\\-1\\1\end{bmatrix}

\overrightarrow{PQ}=\begin{bmatrix}1/2}\\4/3\\-3/4\end{bmatrix}

this is the vector equation of the line segment from P to Q.

to make the parametric equations:

we know that the general equation of a line is represented as:

\overrightarrow{r} = \overrightarrow{r_0} + t\overrightarrow{d}

here, \overrightarrow{r_0}: is the initial position or the starting point. in our case it is the position vector of P

and \overrightarrow{d}: is the direction vector or the direction of the line. in our case that's PQ vector.

\overrightarrow{r} = \begin{bmatrix}0\\-1\\1\end{bmatrix} + t\begin{bmatrix}1/2}\\4/3\\-3/4\end{bmatrix}

that parametric equations can now be easily formed:

\begin{bmatrix}r_x\\r_y\\r_z\end{bmatrix} = \begin{bmatrix}0\\-1\\1\end{bmatrix} + t\begin{bmatrix}1/2}\\4/3\\-3/4\end{bmatrix}

r_x = \dfrac{1}{2}t\\r_y = -1 +\dfrac{4}{3}t\\r_z = 1=\dfrac{3}{4}t

these are the parametric equations of the line PQ

4 0
3 years ago
Please help me please​
Vesnalui [34]
X=7. 42/14=3. so x+5 times 3 = 7x-13. do the math, x =7. 7+5=12. 7(7)-13= 36. 12x3=36. boom.
4 0
3 years ago
Read 2 more answers
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