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andrey2020 [161]
3 years ago
14

Someone help me please

Mathematics
1 answer:
Leni [432]3 years ago
5 0
Whats your question ?? What garde is this ?
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A rectangular field 50 metres wide and x metres long required 260 metres of fencing​
KatRina [158]

Answer:

x=80

Step-by-step explanation:

im going to assume this is perimeter.

50+50=100

260-100=160

160÷2=80

3 0
3 years ago
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Out of 1100 discs tested 13 are defective. Estimate the number of defective discs in a batch of 41000
zvonat [6]
I’d say 485 discs are defective out of 41000
5 0
3 years ago
Use the quadratic formula to solve the following equation -3x^2-x-3=0
tigry1 [53]

<u>Answer:</u>

x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i are two roots of equation -3 x^{2}-x-3=0

<u>Solution:</u>

Need to solve given equation using quadratic formula.

-3 x^{2}-x-3=0

General form of quadratic equation is a x^{2}+b x+c=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}

Since b^{2}-4 a c is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}

8 0
3 years ago
How do you do this ?
jeka57 [31]

Answer: 3(x^2 + 4)/(x - 5)(x + 4)

Step-by-step explanation:

To simplify, begin with 3x^2 + 12 by dividing by 3 first: 3(x^2 + 4)

x^2 - x - 20 can be simplified into (x - 5) (x + 4). To find these terms, you have to figure out what two numbers multiply together to equal -20 but also add to -1.

4 0
3 years ago
What is the answer to -2n + 6 = 12
Pepsi [2]
N= -3 you can check it
4 0
3 years ago
Read 2 more answers
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