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Olegator [25]
3 years ago
10

How many moles of co2 will be produced from 72.0 g of ch4 assuming o2 is available in excess

Chemistry
1 answer:
valina [46]3 years ago
8 0

Moles of CO₂ produced will be 4.5

<u>Explanation:</u>

CH₄ + 2O₂ → CO₂ + 2H₂O

Molecular weight of CH₄, M = 16

given mass of CH₄, m = 72

moles of CH₄, n = given mass / molecular mass

n = \frac{m}{M} \\\\n = \frac{72}{16} \\\\n = 4.5

Therefore, number of moles of CH₄ present is 4.5

According to the balanced equation,

1 mole of CH₄ produces 1 mole of CO₂

4.5 moles of CH₄ will produce 4.5 moles of CO₂

Therefore, moles of CO₂ produced will be 4.5

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What mass of carbon dioxide is produced from the complete combustion of 5.30x10-3 g of methane?
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1.45 x 10⁻² g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams CH₄ to moles CH₄ (via molar mass), then (2) convert moles CH₄ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). The final answer should have 3 sig figs to reflect the given value (5.30 x 10⁻³ g).

Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)

Molar Mass (CH₄): 16.043 g/mol

Combustion of Methane:

1 CH₄ + 2 O₂ ---> 2 H₂O + 1 CO₂

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

5.30 x 10⁻³ g CH₄          1 mole              1 mole CO₂          44.007 g
---------------------------  x  ----------------  x  ---------------------  x  -----------------  =
                                      16.043 g            1 mole CH₄            1 mole

=  0.0145 g CO₂

=  1.45 x 10⁻² g CO₂

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