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3 years ago

5

14. Have your thoughts about the Great Pacific Garbage Patch changed since we first talked about it earlier in the year? Do you

think it is a major concem in the world today? Yes i think...... explain its a opinion question

1 answer:

Llana [10]3 years ago

5 0

Answer:

sowwi I just need the points :(

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Peter ate junk food at breakfast and worried about the examination, which combined to give him an annoying case of acid indigest

vova2212 [387]

Answer:

Consumption of Antacid

Explanation:

At breakfast when Peter ate junk food , excess acid could have got released due to which he had got acidity in his stomach. By consumption of Antacid can reduce the effect of acidity because antacid is a mild base. When a mild base reacts with acid it neutralises the effect of acid & hence gives a relief from acidity...

7 0

3 years ago

What is the mass of a baby in grams if the babies weight in 6 pound. 6 oz

MatroZZZ [7]

2721.55422g

Explanation:

First, step is to find out how much is 1pound in grams.

So,

1 POUND x (1 KG/2.204 POUND) x (1000G/1 KG) which is equal to 453.59g

Here, we got that 1 pound is equal to 453.59g.

In the question, it is given that the weight of the baby is 6 pound.

To convert 6 pounds into grams, we need to multiply 6 pounds with 453.59 g,

6pounds x 453.59g = 2721.55422 g

Hence, the weight of the 6-pound baby in grams will be 2721.55422 grams.

3 0

3 years ago

The mass percent of Cl⁻ in a seawater sample is determined by titrating 25.00 mL of seawater with AgNO₃ solution, causing a prec

Serga [27]

Answer:

2.5 %

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For $AgNO_3$ :

Molarity = 0.2850 M

Volume = 63.30 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 63.30 × 10⁻³ L

Thus, moles of $AgNO_3$ :

$Moles=0.2850 \times {63.30\times 10^{-3}}\ moles$

Moles of $AgNO_3$ = 0.0180405 moles

Moles of $AgNO_3$ = Moles of $Cl^-$

Thus, Moles of $Cl^-$ = 0.0180405 moles

Molar mass of $Cl^-$ = 35.453 g/mol

Mass = Moles * Molar mass = 0.0180405 moles * 35.453 g/mol = 0.6396 g

Volume of sea water = 25.00 mL

Density = 1.024 g/mL

Density = Mass / Volume

Mass = Density * Volume = 1.024 g/mL * 25.00 mL = 25.6 g

$Mass\ \%=\frac{Mass_{Chloride ion}}{Total\ mass}\times 100$

$Mass\ \%=\frac{0.6396}{25.6}\times 100$

<u>Mass percent of Cl⁻ = 2.5 %</u>

4 0

3 years ago

I need help with number 5 please??

AlladinOne [14]

It is a easy one. Keep working and don't stress about it, you'll see, doing this problem alone will securise you

8 0

3 years ago

If a pure compound is distilled, the head temperature will be____compared to the pot temperature. If however, an impurity is pre

shutvik [7]

Answer:

If a pure compound is distilled, the temperature of the head will be compared to the temperature of the pot. However, if there is an impurity present that strongly interacts with the molecules of the liquid, then the temperature must be increased to increase the vapor pressure of the liquid, eventually to atmospheric pressure, allowing the liquid to boil. Therefore, at the boiling point, the temperature of the pot will be higher than the temperature of the head.

Explanation:

when temperatures increase, pressures also do so, thus reaching boiling points where liquid states become gaseous.

4 0

3 years ago