Ask question

Ask question

All categories

3 years ago

5

14. Have your thoughts about the Great Pacific Garbage Patch changed since we first talked about it earlier in the year? Do you

think it is a major concem in the world today? Yes i think...... explain its a opinion question

1 answer:

Llana [10]3 years ago

5 0

Answer:

sowwi I just need the points :(

You might be interested in

Which of the following most accurately describes a regulatory molecule that must be transported to its place of action within th

Sonbull [250]

Answer:

the answer is hormone

Explanation:

because it is

5 0

2 years ago

All organic compounds have at least ____ carbon and two ____

denpristay [2]

All organic compounds have at least 1 carbon and 2 hydrogen atoms.

7 0

3 years ago

For the reaction 2 H2S(g) D 2 H2 (g) + S2 (g), Kp = 1.5 × 10−5 at 800.0°C. If the initial partial pressures of H2 and S2 in a cl

Usimov [2.4K]

Answer: The approximate equilibrium partial pressure of $H_2S$ is 3.92 atm

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

$2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)$

$K_p=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}$

$1.5\times 10^{-5}=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}$

On reversing the reaction:

$2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

initial pressure 4.00atm 2.00 atm 0

eqm (4.00-2x)atm (2.00-x) atm 2x atm

$K_p=\frac{[H_2S]^2}{[H_2]^2\times [S_2]}$

$K_p'=\frac{1}{K_p}=0.67\times 10^5$

$2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

$0.67\times 10^5=\frac{2x]^2}{[4.00-2x]^2\times [2.00-x]}$

$x=1.96$

$[H_2S]=2x=2\times 1.96=3.92 atm$

Thus approximate equilibrium partial pressure of $H_2S$ is 3.92 atm

3 0

3 years ago

How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?

puteri [66]

5.4 M = moles of solute / 1.50 L

<span>Multiply both sides by 1.50 L to isolate moles of solute on the right. </span>

<span>8.1 mol = moles of solute </span>

6 0

3 years ago

Read 2 more answers

A student makes a mistake while preparing a vitamin C sample for titration and adds the potassium iodide solution twice. How wil

LiRa [457]

The added KI does not have any impact

The reaction invovles Titration of vitaminc ( Ascorbic acid)

ascorbic acid + I₂ → 2 I⁻ + dehydroascorbic acid

the excess iodine is free reacts with the starch indicator, forming the blue-black starch-iodine complex.

This is the endpoint of the titration. since alreay excess KI is added ( the source of Iodine), it does not have an influence.

Answer B

Hope this helps!

5 0

4 years ago