Answer:
Moles of magnesium chloride can be produced are 0.2 moles
Explanation:
The reaction of Mg with Cl2 is:
Mg + Cl₂ → MgCl₂
<em>Where 1 mole of Mg reacts per mole of Cl₂ to produce MgCl₂.</em>
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As the reaction is 1:1, we need to convert the mass of both Mg and Cl₂ to moles. The lower number of moles will determine the moles of MgCl₂ that will be produced:
<em>Moles Mg -Molar mass: 24.3g/mol-:</em>
4.86g * (1mol / 24.3g) = 0.2 moles Mg
<em>Moles Cl₂ -Molar mass: 24.3g/mol-:</em>
21.27g * (1mol / 70.9g) = 0.3 moles Cl₂
As moles of Mg < moles of Cl₂, Mg is limiting reactant and moles of magnesium chloride can be produced are 0.2 moles
Answer:
10.60 grams of silane gas are formed.
Explanation:
From the reaction:
Mg₂Si(s) + 4H₂O(l) → 2Mg(OH)₂(aq) + SiH₄(g)
We know that the limiting reactant is Mg₂Si, so to find the mass of SiH₄ formed we need to calculate the number of moles of Mg₂Si:
Where:
m: is the mass of Mg₂Si = 25.0 g
M: is the molar mass of Mg₂Si = 76.69 g/mol
Now, the stoichiometric relation between Mg₂Si and SiH₄ is 1:1 so:
Finally, the mass of SiH₄ is:
Therefore, 10.60 grams of silane gas are formed.
I hope it helps you!
Answer:
The answer is
<h2>11.18 cm³</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 123 g
density = 11.3 g/cm³
The volume is
We have the final answer as
<h3>11.18 cm³</h3>
Hope this helps you
Answer:
5Atm
Explanation:
I just guess and it’s right
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