Answer: 67.23 L
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
To calculate the number of moles, we use the equation:
Putting in the values we get:
1 mole of methane occupies = 22.4 L
Thus 3 moles of methane occupy = 
Thus volume of 48 grams of methane gas is 67.23 L
At a temperature of 30 deg C, the vapour pressure of water
H2O is about 32 mm Hg. Therefore at a total pressure f 734 mm Hg, the partial
pressure of the Hydrogen gas collected is:
<span>P Hydrogen = 734 mm Hg – 32 mm Hg = 702 mm Hg</span>
Answer:
The mechanism for the formation of hexamethylenetetraamine predicts the formation of aminomethanol from the addition of ammonia to formaldehyde. This molecule subsequently undergoes unimolecular decomposition to form methanimine and water.
Explanation:
Brainliest please?
