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Bas_tet [7]
2 years ago
5

Using the formula M1V1 = M2V2 , how many milliliters of a 2. 50 M hydrochloric acid solution is required to make 100. 0 mL of a

0. 750 M solution?.
Chemistry
1 answer:
gladu [14]2 years ago
3 0

Dilution of the solution can be calculated by the formula of the molarity and volume. The initial volume of 2.50 M solution was 30 mL.

<h3>What is the relationship between molar concentration and dilution?</h3>

Molar concentration or the dilution factor is in an inverse relationship and with an increase in the dilution, the molarity of the solution decreases.

Given,

Initial molarity = 2.50 M

initial volume = ?

Final molarity = 0.750 M

Final volume = 100.0 ml

Substituting values in the formula:

\begin{aligned}\rm V_{1} &= \rm \dfrac{M_{2}V_{2}}{M_{1}}\\\\&= \dfrac{0.750 \times 100}{2.50}\\\\&= 30 \;\rm mL\end{aligned}

Therefore, 30 mL was the initial volume of the solution before it was diluted.

Learn more about dilution here:

brainly.com/question/26896011

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What is the volume in a 2. 00M solution containing 8.00 moles of solute?
MrMuchimi

Answer:

4000cm³

Explanation:

2.0moles-1000cm³

8.0moles-?

(8.0×1000)÷2

=4000cm³

5 0
3 years ago
A postulate of the kinetic molecular theory is listed.
valina [46]

Answer:

Postulate: Gas particles are extremely small and are far apart.

The activities can be used to demonstrate the postulate is :

<u>Observing colored gas spreading into an inverted jar placed on top of a jar containing the gas</u>

<u />

Explanation:

colored gas spreading into an inverted jar placed on top of a jar containing the gas:

This occur because of two reasons:

1. <em><u>The Gaseous particles are largely spaced . There is large distance between the gases molecule</u></em>

<em><u>2. The gases are in continuous motion . Hence they posses very high kinetic energy . This is the reason they mixes quickly if placed in a jar.</u></em>

<em><u>This occur by the process of diffusion. </u></em>

Diffusion of Gases: The intermixing of particles from the region of high concentration to low concentration.

The coloured gas goes into the space between the gaseous molecule present in the jar.(Gases are far apart)

As soon as the coloured gas is mixed in the jar , It spread quickly by diffusion because , The gaseous particles are extremely small and are far apart.

5 0
3 years ago
If you were making S’mores [using a chocolate bar, gram-crackers, and marshmallows] at a campfire, would this process be conside
OLga [1]

Answer:

The process of making S'more by adding chocolate bar, gram-crackers, and marshmallows in layers is not a chemical reaction

Explanation:

In a chemical reaction, the substances involved in the reaction are known as the reactants and the substances produced have different physical and chemical properties than those of the reactants and they are known as the products.

The bonds that hold the atoms of the reactants are broken down and rearranged, creating entirely new substances as products. Therefore, energy must be added and/or evolved in any chemical reaction and all reactant atoms should be involved in the reaction.

The change in energy can be sensed as heat change such as increase or decrease in the temperature of the products

Since S'more does not involve any of the above changes that occur in a chemical reaction when the chocolate bar, gram-crackers, and marshmallows are put together, it is not a chemical change or a chemical reaction.

3 0
3 years ago
A covalent bond forms
Natalka [10]
B.) When atoms share electrons/......
8 0
3 years ago
The coolant in automobiles is often a 50/50 % by volume mixture of ethylene glycol, C2H6O2, and water. At 20°C, the density of e
Misha Larkins [42]

Explanation:

Let the volume of the solution be 100 ml.

As the volume of glycol = 50 = volume of water

Hence, the number of moles of glycol = \frac{mass}{molar mass}

                                                  = \frac{density \times volume}{molar mass}

                         = \frac{1.1088 \times 50}{62 g/mol}

                         = 0.894 mol

Hence, number of moles of water = \frac{50 \times 0.998}{18}

                                             = 2.77

As glycol is dissolved in water.

So, the molality = 0.894 \times \frac{1000}{49.92}

                           = 17.9

Therefore, the expected freezing point = -1.86 \times 17.9

                                                                  = -33.31^{o}C

Thus, we can conclude that the expected freezing point is -33.31^{o}C.

6 0
2 years ago
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