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NNADVOKAT [17]
3 years ago
11

A solution contains 11% by mass of sodium chloride. this means that __________.

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
5 0

As a solution is contained with 11% by mass of sodium chloride, this will therefore conclude that the 100g of the solution is composed of the 11g of the sodium chloride. In which, the correct answer would be specified as letter c.

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How many moles of MgO can be made from 5 moles of Mg?<br> 2Mg + O2 -&gt; 2MgO
kkurt [141]

Answer:

Explanation:

The expected product is MgO, so the 1-to-1 mole ratio Mg to O in the product is all that is required.

3 0
2 years ago
Determine whether each statement is a description of a physical property or a chemical property. Please check the box that appli
aleksklad [387]
Conductivity is a physical property

Odor is also a physical property
7 0
2 years ago
Two perfumes are released at the same time. If one is standing 7.5 m from the point of release. Perfume A (molar mass 275 g/mol)
natta225 [31]
According to Graham's Law of Diffusion," Diffusion of Gas is inversely proportional to square root of its Molecular Mass or Density".

                          rᵇ/rᵃ  =  \sqrt{da/db}
Or,
                          rᵇ/rᵃ  =  \sqrt{Ma/Mb}     ----- (1)
As, 
                          Ma  =  275 g/mol

                          Mb  =  205 g/mol

Putting Values in eq.1,

                          rᵇ/rᵃ  =  \sqrt{275/205}

                          rᵇ/rᵃ  =  1.15

Result:
          Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.
6 0
2 years ago
Is this correct?? please help​
NeTakaya

Yes it is but I have to check so wait

4 0
2 years ago
What is the molarity of the potassium hydroxide if 25.25 mL of KOH is required to neutralize 0.500 g of oxalic acid, H2C2O4? H2C
Greeley [361]

Answer:

0.444 mol/L

Explanation:

First step is to find the number of moles of oxalic acid.

n(oxalic acid) = \frac{0.5g}{90.03 g/mol} = 5.5537*10^{-3} mol\\

Now use the molar ratio to find how many moles of NaOH would be required to neutralize 5.5537*10^{-3} mol\\ of oxalic acid.

n(oxalic acid): n(potassium hydroxide)

         1           :            2                  (we get this from the balanced equation)

5.5537*10^{-3} mol\\ : x

x = 0.0111 mol

Now to calculate what concentration of KOH that would be in 25 mL of water:

c = \frac{number of moles}{volume} = \frac{0.0111}{0.025} = 0.444 mol/L

5 0
3 years ago
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