Answer:
Covalent bonding occurs when electrons are shared between atoms. Double and triple covalent bonds occur when four or six electrons are shared between two atoms, and they are indicated in Lewis structures by drawing two or three lines connecting one atom to another.
Explanation:
Answer:
1.10 g/L
Explanation:
Step 1: Calculate Henry's constant (k)
The solubility of a gas (C) is 0.890 g/L at a pressure (P) of 121 kPa. Solubility and pressure are related through Henry's law.
C = k × P
k = C / P
k = (0.890 g/L) / 121 kPa = 7.36 × 10⁻³ g/L.kPa
Step 2: Calculate the solubility of the gas if the pressure is increased to 150 kPa
We will use Henry's law.
C = k × P
C = (7.36 × 10⁻³ g/L.kPa) × 150 kPa = 1.10 g/L
Answer:
Following are the answer to this question:
Explanation:
The answer are:
1) ketopentose
2) Triose
3) Aldose
4) Ketose
5) Glucose
6) Aldohexose
- The pentose has 2-position contain a personal ketone group.
- The triose is a monosaccharide or simple sugar that contains three atoms of carbon.
- The Aldose and ketose are simple carbohydrates, both also called monosaccharides. In aldose, it has a functional group of aldehydes within its structure. The ketose sugars have workable ketone groups. Stereoisomerism has been found in aldose sugars that contain more than three carbon atoms.
- Glucose is also one of the main molecules which function as plant and animal energy sources. It's also derived from plant sap and seems to be present in the bloodstream of humans, that's why it is called "blood sugar."
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The aldohexose is a hexose is a group of aldehydes on one end, it has a total of 16 possible aldohexose stereoisomers in four chiral centers.
Answer:
Product formed is octan-3-one.
Explanation:
is a Gilman reagent. General formula of Gilman reagent is .
Where R is alkyl group or aryl group.
Gilman reagents react with the organo halides to replace halides with alkyl group or aryl group and this reaction is known as Corey–House synthesis.
When hexanoyl chloride is treated with , the chloride group of the hexanoyl chloride is substituted with the ethyl group of the to form octan-3-one with the removal of EtCu and LiCl.