Please help thank you
1 answer:
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Answer:
13.57 kg
Step-by-step explanation:
Let the amount of salt in a tank be =
=
= 0.3 kg/L
The concentration of salt coming into the tank = 0.333kg/L
We know that the concentration of salt leaving the tank should be:
amount of salt in the tank/volume of tank = y(t)/50 L
rate of change of salt = rate in - rate out
= 0.66 -
solving the differential equation gives :
ln y = 0.66/y (t) - 0.02 t + C
Initial conditions, t= 0; y (0) = 15
then ln 15 = C
ln y = t - 0.02t + ln 15
ln = 0.02t
y = 15e( exp -0.02t)
the amount of salt in 5 mins will be:
y (t) = 15e(exp -0.02 (5)
= 13.57 kg