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3 years ago

10

a vet measured the mass of two birds.The mass of robin was 76.64 grams.the mass of the blue jay was 81.54 grams estimate the dif

ference in the masses of the birds

1 answer:

Bond [772]3 years ago

3 0

well for this one all u have to do is estimate to the closer number then subtract

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PLS HELP ILL MARK BRAINLIEST ITS URGENT

Nataliya [291]

Answer:

(x^2 + x -1) x (x^2+3x-3)

Step-by-step explanation:

-6x-5+x^4+4x^3-x^2+8

-6x+3+x^4+4x^3-x^2

-6x+3+x^4+x^3+3x^3-x^2

-3x-3x+3+x^2 x(x^2+x-1)+3x^3 +3x^2-3x^2

3x *(x^2+x+x-2)-3(x^2+x-1)+x^2 *(x^2+x-1)

= (x^2+x-1) x (x^2+3x-3)

* means multiply btw

8 0

3 years ago

What is the solution of the equation 11 – 4x = 5? round your answer to the nearest ten-thousandth?

OLga [1]

11-4x=5
4x=6
x=6/4=1.5000

5 0

3 years ago

Read 2 more answers

One of the great mysteries of the world is my hotdogs and hotdog buns come in packages of different sizes hotdogs come in packs

V125BC [204]

Answer:

3 pack of hot dogs and 2 pack of buns 24

Step-by-step explanation:

hot dogs come in packs of 8

burns came in packs of 12

what is the least number of each you can buy in order to have a equal number of hot dogs and buns

so to get equal number

we have to look for the LCM of 8 and 12 = 24

therefore the packs will be equal to product

hot dogs come in packs of 8 = 8*3 = 24

burns came in packs of 12 = 12 *2 = 24

therefore, 3 pack of hot dogs and 2 pack of buns 24

7 0

3 years ago

Simplify: 10 • 12 + - 15 divided by 5 + 2 (9-4)

Ket [755]

Alright. So the problem is

10*12+-15/5+2(9-4)

Lets break down what we can for now

First focus on parenthesized, multiplying, and dividing in the problem.

10*12=120 15/5=3 (9-4)=5

120+-3+2*5

So the next step, we see 2*5 and a negative -3 on top of a positive symbol.

2*5=10

120-3+10

Now subtract from the left to the right and get your answer.

120-3=117

117+10=127

7 0

4 years ago

A publisher reports that 344% of their readers own a particular make of car. A marketing executive wants to test the claim that

inysia [295]

Answer:

No, there is not enough evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

We are given that a publisher reports that 34% of their readers own a particular make of car. A random sample of 220 found that 30% of the readers owned a particular make of car.

And, a marketing executive wants to test the claim that the percentage is actually different from the reported percentage, i.e;

Null Hypothesis, $H_0$ : p = 0.34 {means that the percentage of readers who own a particular make of car is same as reported 34%}

Alternate Hypothesis, $H_1$ : p $\neq$ 0.34 {means that the percentage of readers who own a particular make of car is different from the reported 34%}

The test statistics we will use here is;

T.S. = $\frac{\hat p -p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } }$ ~ N(0,1)

where, p = actual % of readers who own a particular make of car = 0.34

$\hat p$ = percentage of readers who own a particular make of car in a

sample of 220 = 0.30

n = sample size = 220

So, Test statistics = $\frac{0.30 -0.34}{\sqrt{\frac{0.30(1- 0.30)}{220} } }$

= -1.30

Now, at 0.02 significance level, the z table gives critical value of -2.3263 to 2.3263. Since our test statistics lie in the range of critical values which means it doesn't lie in the rejection region, so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the actual percentage of readers who own a particular make of car is same as reported percentage and the executive's claim that it is different is not supported.

3 0

3 years ago