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3 years ago

10

a vet measured the mass of two birds.The mass of robin was 76.64 grams.the mass of the blue jay was 81.54 grams estimate the dif

ference in the masses of the birds

1 answer:

Bond [772]3 years ago

3 0

well for this one all u have to do is estimate to the closer number then subtract

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Which of the following functions is graphed below?

erastovalidia [21]

Could you please attach the graph itself because the question is not proper

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3 years ago

Erica uses 9 gallons of gas to drive 198 miles. How many miles can he drive using 1 gallon of gas?

lara31 [8.8K]

Answer:

198 / 9 = 22

Step-by-step explanation:

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3 years ago

Find the values of the sine, cosine, and tangent for ZA C A 36ft B <br> 24ft

Reptile [31]

<h2>Question:</h2>

Find the values of the sine, cosine, and tangent for ∠A

a. sin A = $\frac{\sqrt{13} }{2}$ , cos A = $\frac{\sqrt{13} }{3}$ , tan A = $\frac{2 }{3}$

b. sin A = $3\frac{\sqrt{13} }{13}$ , cos A = $2\frac{\sqrt{13} }{13}$ , tan A = $\frac{3}{2}$

c. sin A = $\frac{\sqrt{13} }{3}$ , cos A = $\frac{\sqrt{13} }{2}$ , tan A = $\frac{3}{2}$

d. sin A = $2\frac{\sqrt{13} }{13}$ , cos A = $3\frac{\sqrt{13} }{13}$ , tan A = $\frac{2 }{3}$

<h2>Answer:</h2>

d. sin A = $2\frac{\sqrt{13} }{13}$ , cos A = $3\frac{\sqrt{13} }{13}$ , tan A = $\frac{2 }{3}$

<h2>Step-by-step explanation:</h2>

The triangle for the question has been attached to this response.

As shown in the triangle;

AC = 36ft

BC = 24ft

ACB = 90°

To calculate the values of the sine, cosine, and tangent of ∠A;

<em>i. First calculate the value of the missing side AB.</em>

<em>Using Pythagoras' theorem;</em>

⇒ (AB)² = (AC)² + (BC)²

<em>Substitute the values of AC and BC</em>

⇒ (AB)² = (36)² + (24)²

<em>Solve for AB</em>

⇒ (AB)² = 1296 + 576

⇒ (AB)² = 1872

⇒ AB = $\sqrt{1872}$

⇒ AB = $12\sqrt{13}$ ft

From the values of the sides, it can be noted that the side AB is the hypotenuse of the triangle since that is the longest side with a value of $12\sqrt{13}$ ft (43.27ft).

<em>ii. Calculate the sine of ∠A (i.e sin A)</em>

The sine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the hypotenuse side of the triangle. i.e

sin Ф = $\frac{opposite}{hypotenuse}$ -------------(i)

<em>In this case,</em>

Ф = A

opposite = 24ft (This is the opposite side to angle A)

hypotenuse = $12\sqrt{13}$ ft (This is the longest side of the triangle)

<em>Substitute these values into equation (i) as follows;</em>

sin A = $\frac{24}{12\sqrt{13} }$

sin A = $\frac{2}{\sqrt{13}}$

<em>Rationalize the result by multiplying both the numerator and denominator by </em> $\sqrt{13}$ <em />

sin A = $\frac{2}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }$

sin A = $\frac{2\sqrt{13} }{13}$

<em>iii. Calculate the cosine of ∠A (i.e cos A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the adjacent side to that angle to the hypotenuse side of the triangle. i.e

cos Ф = $\frac{adjacent}{hypotenuse}$ -------------(ii)

<em>In this case,</em>

Ф = A

adjacent = 36ft (This is the adjecent side to angle A)

hypotenuse = $12\sqrt{13}$ ft (This is the longest side of the triangle)

<em>Substitute these values into equation (ii) as follows;</em>

cos A = $\frac{36}{12\sqrt{13} }$

cos A = $\frac{3}{\sqrt{13}}$

<em>Rationalize the result by multiplying both the numerator and denominator by </em> $\sqrt{13}$ <em />

cos A = $\frac{3}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }$

cos A = $\frac{3\sqrt{13} }{13}$

<em>iii. Calculate the tangent of ∠A (i.e tan A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the adjacent side of the triangle. i.e

tan Ф = $\frac{opposite}{adjacent}$ -------------(iii)

<em>In this case,</em>

Ф = A

opposite = 24 ft (This is the opposite side to angle A)

adjacent = 36 ft (This is the adjacent side to angle A)

<em>Substitute these values into equation (iii) as follows;</em>

tan A = $\frac{24}{36}$

tan A = $\frac{2}{3}$

6 0

3 years ago

What is the uniqueness of comeplex integration from line integaration?

ella [17]

In normal line integration, from what I understand, you are measuring the area underneath (,)
f
(
x
,
y
)
along a curve in the -
x
-
y
plane from point
a
to point
b
.

3 0

3 years ago

Write an equation in slope intercept form for the line with slope -2/3 and y-intercept -5

dalvyx [7]

Answer:

$y = - \frac{2}{3} x - 5$

Step-by-step explanation:

slope intercept form is y =mx+b

m is the slope

b is the y intercept

if you have any questions feel free to ask :)

4 0

3 years ago