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Andre45 [30]
3 years ago
10

The y-component of the force F which a person exerts on the handle of the box wrench is known to be 86 lb. Determine the x-compo

nent and the magnitude of F.

Physics
1 answer:
emmainna [20.7K]3 years ago
5 0

Answer:

x-component of force is  38.18 lb where as magnitude of Force is 93.16

Explanation:

Fy of the force F exerted on the handle of the box wrench = 86 lb

Considering the triangle in Fig 1

magnitude of perpendicular = P =  12

magnitude of base = B = 5

using Pythagoras theorem

                        H= \sqrt{P^{2} + B^{2}}

                 H= \sqrt{12^{2} + 5^{2}}

            H=13\\\implies cos \theta = \frac{5}{13} \\\implies sin \theta = \frac{12}{13}\\

y-component of force is given given as:

                              86 = Fsin\theta\\F = 86 (\frac{13}{12})\\F = 93.16 lb\\F_{x} =F cos \theta\\F_{x} = 93.16 (\frac{5}{13})\\F_{x} =38.18 lb.

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Anna007 [38]

Answer:

rotation and revolution

Explanation:

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movement of the whole solar system with space),  only two are of any

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6 0
3 years ago
For this triangle...?
Mariulka [41]
<h3><u>Answer</u>;</h3>

= 0.6

<h3><u>Explanation</u>;</h3>

Using Pythagoras theorrem

Base² + height ² = Hypotenuse²

Thus;

Base² = 15² - 12²

          = 81

Base = √81 = 9

But; cosine = adjacent/hypotenuse

Hence; cos θ = 9/15

                      <u>= 0.6 </u>

5 0
3 years ago
Read 2 more answers
Plz help need answer ASAP thanks
MAVERICK [17]
It’s procedural memory Bc idk but procedural is how to do something and declarative is remembering something
3 0
3 years ago
The components of vector A are Ax = +2.2 and Ay = -6.9 , and the components of vector B are given are Bx = -6.1 and By = -2.2. W
Zina [86]
For simplicity, let's call vector B-A  vector C  Then C is
Cx = (-6.1 - 2.2)  
Cy = (-2.2 - (-6.9))  Or,
Cx = -8.3  Cy = 4.7
The magnitude is found with the Pythagorean theorem
||C|| = √(-8.3² + 4.7²) = 9.538
3 0
3 years ago
An object of mass m is traveling in a circle with centripetal force Fc. If the velocity of the object is v, what is the radius o
borishaifa [10]

Hi there!

Recall the equation for centripetal force:
F_c = \frac{mv^2}{r}

We can rearrange the equation to solve for 'r'.

Multiply both sides by r:
r * F_c = mv^2

Divide both sides by Fc:
\boxed{ r= \frac{mv^2}{F_c}}

7 0
2 years ago
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