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umka21 [38]
2 years ago
12

Why is animal husbandry important for human ?​

Physics
2 answers:
Marat540 [252]2 years ago
7 0

Answer:

Here's <em>your</em><em> </em><em>answer</em>

Explanation:

<u>Animal</u><u> </u><u>rearing</u><u> </u><u>is </u><u>important</u><u> </u><u>for </u><u>h</u><u>u</u><u>mans </u><u>as </u><u>they </u><u>attain </u><u>a </u><u>wide </u><u>range</u><u> of</u><u> </u><u>food</u><u> </u><u>products</u><u> </u><u>having</u><u> </u><u>high </u><u>nutrients</u><u> </u><u>quantity</u><u> </u><u>.</u><u>They </u><u>meet </u><u>the </u><u>commerical </u><u>requirements</u><u> </u><u>for </u><u>high </u><u>demand</u><u> </u><u>of </u><u>foods </u><u>such </u><u>as </u><u>dairy</u><u> </u><u>needs </u><u>from </u><u>co</u><u>w</u><u>s </u><u>,</u><u> </u><u>goats </u><u>and </u><u>buffaloes</u>

Svetradugi [14.3K]2 years ago
3 0

Explanation:

Animal rearing is important for humans as they attain a wide range of food products having high nutrient values. They meet the commercial requirements of high demand for food such as dairy needs from cows, goats, and buffaloes.Animal husbandry helps in the proper management of animals by providing proper food, shelter and protection against diseases to domestic animals. It provides employment to a large number of farmer and thereby increases their living standards. It helps in developing high yielding breeds of animals by cross breeding

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The force F required to compress a spring a distance x is given by F 2 F0 5 kx where k is the spring constant and F0 is the prel
IrinaVladis [17]

Answer:

a)W=8.333lbf.ft

b)W=0.0107 Btu.

Explanation:

<u>Complete question</u>

The force F required to compress a spring a distance x is given by F– F0 = kx where k is the spring constant and F0 is the preload. Determine the work required to compress a spring whose spring constant is k= 200 lbf/in a distance of one inch starting from its free length where F0 = 0 lbf. Express your answer in both lbf-ft and Btu.

Solution

Preload = F₀=0 lbf

Spring constant k= 200 lbf/in

Initial length of spring x₁=0

Final length of spring x₂= 1 in

At any point, the force during deflection of a spring is given by;

F= F₀× kx  where F₀ initial force, k is spring constant and x is the deflection from original point of the spring.

W=\int\limits^2_1 {} \, Fds \\\\\\W=\int\limits^2_1( {F_0+kx} \,) dx \\\\\\W=\int\limits^a_b {kx} \, dx ; F_0=0\\\\\\W=k\int\limits^2_1 {x} \, dx \\\\\\W=k*\frac{1}{2} (x_2^{2}-x_1^{2}  )\\\\\\W=200*\frac{1}{2} (1^2-0)\\\\\\W=100.lbf.in\\\\

Change to lbf.ft by dividing the value by 12 because 1ft=12 in

100/12 = 8.333 lbf.ft

work required to compress the spring, W=8.333lbf.ft

The work required to compress the spring in Btu will be;

1 Btu= 778 lbf.ft

?= 8.333 lbf.ft----------------cross multiply

(8.333*1)/ 778 =0.0107 Btu.

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