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Nostrana [21]
3 years ago
14

Select the alkyne listed below that, upon treatment with ozone followed by water, would not produce carbon dioxide and a carboxy

lic acid as the final products?
O 1-Pentyne
O Propyne
O 1-Butyne
O 1-Hexyne
O Ethyne
Chemistry
1 answer:
GalinKa [24]3 years ago
5 0

Answer:

The only exception is Ethyne

Explanation:

Homologous members of alkynes formed ozonide and when treated with ozone and water, then decomposed to form ketones which are then oxidized to carbon dioxide and carboxylic acids.

Ethyne( Acetylene) is an exception as it gives glyoxal as well as formic acid on reacting with ozone.

C2H2 + O3 ==> OCHCHO + HCO2H

Therefore, Ethyne is the only exception.

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When 42.5 g of benzamide (C7H7NO) are dissolved in 500 g of a certain mystery liquid X, the freezing point of the solution is 6.
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Answer:

21.3g of Fe(NO₃)₃ are required to produce the same depression in freezing point of solution.

Explanation:

Freezing point depression is a colligative property which indicates, in determined mixture, the freezing point of solution is lower that the freezing point of the solvent, according the amount of solute.

Formula is: ΔT = Kf . m . i

Kf is the cryoscopic constant, which is particular for each solvent. We do not have that data, so we need to find it out in order to solve the question:

ΔT = Freezing point of pure solvent - Freezing point of solution.

This data is known → 6.40°C

m, means molality, moles of solute in 1kg of solvent. Let's get the moles of benzamide: 42.5 g . 1mol / 121g = 0.351 moles

m = 0.351 mol / 0.5kg = 0.702 m

As benzamide is an organic compound i, = 1. i are the number of ions dissolved in solution. Let's find out Kf:

6.40°C = Kf . 0.702 m . 1

6.40°C /0.702m = 9.11 °C/m.

Let's go to the next question.

ΔT is the same → 6.40°C

But this is, an inorganic salt, a ionic salt: Fe(NO₃)₃ →  1Fe³⁺  + 3NO₃⁻

For this case, we have 1 mol of Iron(III) and 3 nitrates, so i = 4

Let's replace data: 6.40°C = 9.11 °C/m . m . 4

6.40°C / (9.11 m/°C . 4) = 0.176 m

This data represents that, in 1 kg of solvent we have 0.176 moles of nitrate.

Mass of solvent X required in this case is 0.500 kg, so, the moles that are contained are: 0.500 kg . 0.176 mol/kg = 0.088 mol

Let's determine the mass of salt: 0.088 mol . 241.85g /1mol = 21.3 g

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