When orthobromoanisole is treated with sodamide (NaNH₂) and ammonia (NH₃), benzyne is formed and the tripple bond is formed between C₂-C₃ carbon atoms of benzene ring. Then NH₂⁻ can attack at ortho position as well as meta position.
The reaction takes place in three steps. Step-1:The amide NH₂⁻ ion attacks the H
-atom that is ortho to C3
, generating a carbanion. Step-2:Loss of Br
- to form a benzyne intermediate.Step-3:Addition of NH₂⁻ ion. The strain caused by a triple bond in a benzene ring can be relieved by a nucleophilic addition of NH₂⁻.
Two isomeric products are formed: (1) <em>o</em>-methoxyaniline and (2) <em>m</em>-methoxyaniline. The structures of both the isomeric products are given in diagram.
Answer:
B, 2.22×10^22 molecules
Explanation:
Given PV=nRT, n=PV/RT
n=103.7×1.0/8.314×(65+273.15)
= 0.0368858... moles
Given n= number of particles/avogadros number
number of particles=n×avogadros number
number of particles = 0.03688...×6.02x10^23
= 2.22×10^22 molecules
I believe B is the correct answer
Answer:
3.6 times 10^4
Explanation:
Scientific notation is between 1-9. So, we move 36000 to 4 decimal places. SO it would be 3.6 times 10^4. Scientific Notation always has the base of 10 . Enjoy :)
Idk but I’ll try to answer