1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natasha_Volkova [10]
3 years ago
7

Solve 0.7x-2<5.5 and graph the solution on a number line

Mathematics
1 answer:
ale4655 [162]3 years ago
5 0
0.7x-2

x < (75/7)
You might be interested in
Help I need this badlyuu
Alex Ar [27]
It is 2/3 I believe

By calculating the difference between the x and y coordinates, and putting it in the rise/run format, you can easily find the slope of the line
4 0
2 years ago
Compare Decima<br> 2.48 [. ] 2.53<br><br> I need help finishing if this is a &lt;,&gt; or =
lorasvet [3.4K]

Answer: <

Step-by-step explanation:

2.48 < 2.53

7 0
3 years ago
-7 (-7)^-4 plz help plz
Natali5045456 [20]

Answer: -1/343

Step-by-step explanation:

-7(-7)^-4

First, re-write as positive exponents:

-7(-1/7^4)

Next, simplify:

-1/7^3 (you can simplify using exponent rules)

Simplify 7^3 :

7(7)(7)

49(7)

343.

Insert to original expression:

-1/343.

5 0
3 years ago
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
3 years ago
A consumer charges a 2530.16 purchase on the credit card the card has a daily interest rate of .042% if the consumer piece of th
svp [43]

Answer:

$31.88

Step-by-step explanation:

Given

Consumer charges = 2530.16cents

Consumer charges in dollars = $25.3016

Interest rate per day = 0.042%

Interest gotten per day = 0.042×25.3016

Interest per day = $1.06266

Interest in 30 days = ,30×1.06266

Interest in 30 days = $31.88

3 0
3 years ago
Other questions:
  • If (f + g)(x) = 3x2 + 2x – 1 and g(x) = 2x – 2, what is f(x)
    14·1 answer
  • while exercising victor walked 1/8 of a mile in 1/9 of an hour. at this rate, how far will he travelled after an hour?
    5·2 answers
  • THE IMAGE DOWN BELOW MATH PLEASE HELP ME WITH THIS ALEGEBRA IM CRYING YALL
    13·1 answer
  • Por favor denme una ecuación a esta pregunta:
    8·1 answer
  • Simplify the expression 2(x+4)−3(x+2).
    13·1 answer
  • Calcule o valor de x, sabendo que as retas “e” “f” e “a” são paralelas
    13·1 answer
  • What does it mean to share an amount in the ratio 3:7
    7·2 answers
  • Convert the angle 0=228 degrees to radians
    15·1 answer
  • 2x+7y =3<br> x= -4y <br><br> x=<br> y=
    5·2 answers
  • The polygons are similar, but not necessarily drawn to scale. Find the value of x. PLEASE HELPPPP
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!