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ratelena [41]
3 years ago
5

Find two consecutive even integers such that five times the smaller integer is ten more than three times the larger integer.

Mathematics
1 answer:
quester [9]3 years ago
8 0
5n = 3(n + 2) + 10
5n = 3n + 16
12n = 16 
n = 8  

8 is smaller integer and 10 is the larger.
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Least to greatest 16,-37,51,61
sashaice [31]
-37,16,51,61
negative numbers are always less than positive numbers
5 0
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Lola takes the train from Paris to Nice. The distance between the two cities is about 921,000 meters. If the train travels at a
Andru [333]
Distance =rate/time so your answer is 3 hours first you have to convert meters to kilometers 921000 meters = 921 Km so you have like terms to calculate so your distance becomes 921 Km then divide by the speed 907÷3 = 3 so your answer is 3 hrs
7 0
3 years ago
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Alec says the sum of two numbers can never be less than either number.
STatiana [176]

Answer:

If you put two things together it cannot be less than what was originally there.

Step-by-step explanation:

For example if you have two bowls of soup and you add them together you will have more soup.

4 0
2 years ago
A rectangular piece of metal is 30 in longer than it is wide. Squares with sides 6 in long are cut from the four corners and the
snow_lady [41]

Answer = 55,25 inches

Solution -

let's take x as length and y as width of the metal piece. As per the question x is 30 more than y,

⇒ x = y + 30

Then four square pieces of side 6 are cut from each corner,

so the new length and width are

x-12 , y-12

Then the volume of the new box created will be

(x-12)(y-12)6

in the question the volume of the given figure is given to be 3354

so (x-12)(y-12)6 = 3354

putting the value of x in the the above equation

⇒ (y+30 - 12)(x-12) = 3354/6 = 559

⇒ (y+18)(y-12) = 559

⇒ y² + 6y - 775 = 0

⇒ y² + 31y - 25y -775 = 0

⇒ (y+31)(y-25) = 0

⇒ y = -31, 25

as length can not be -ve , so y = 25

then x = 25+30 = 55

Hence the dimensions of the metal piece are 55, 25 inches

3 0
3 years ago
Which strategy best explains how to solve this problem?
Rufina [12.5K]
This is a geometric sequence because each term is twice the value of the previous term.  So this is what would be called the common ratio, which in this case is 2.  Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number

In this case we have r=2 and a=1 so

a(n)=2^(n-1)  so on the sixth week he will run:

a(6)=2^5=32

He will run 32 blocks by the end of the sixth week.

Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:

s(n)=a(1-r^n)/(1-r)  where the variables have the same values so

s(n)=(1-2^n)/(1-2)

s(n)=2^n-1 so 

s(6)=2^6-1

s(6)=64-1

s(6)=63 blocks

So he would run a total of 63 blocks in the six weeks.
4 0
3 years ago
Read 2 more answers
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