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seropon [69]
3 years ago
14

2KI + Pb(NO3)2 → 2KNO3 + PbI2

Chemistry
1 answer:
lara31 [8.8K]3 years ago
5 0
Hello!

This question can be easily solved using the Mole Ratio of KNO₃/KI in the balanced reaction that is shown below:

2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂

The Mole Ratio of KNO₃/KI in this reaction is 2 moles KNO₃/ 2 moles KI so we can apply the following conversion factor:

0,03 moles KI * \frac{2 moles KNO_3}{2 moles KI}=0,03 moles KNO_3

So, if 0,03 moles of KI are completely consumed, 0,03 moles of KNO₃ are formed.

Have a nice day!
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